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expeople1 [14]
3 years ago
6

Dichlorosilane is a compound that contains silicon (Si), hydrogen (H), and chlorine (Cl) atoms. It has the chemical formula SiH2

Cl2. Which statement accurately describes dichlorosilane?
Each molecule contains two chlorine atoms.
Each molecule contains three atoms.
Each molecule contains five different elements.
Each molecule contains five compounds.

A or D?
Chemistry
1 answer:
Doss [256]3 years ago
6 0
I think the correct answer is A. Dichlorosilane has a formula of SiH2Cl2. As we can see, for every mole of this compound there will be two atoms of chlorine, two atoms of hydrogen and one atom of silicon. There are 3 different types of atoms involved. And all of this makes up a compound.
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Please balance the equation C7H16 + CoF3 = C7F16 + HF +CoF2<br> with solutions
Andrei [34K]

Answer:

C₇H₁₆ + 32CoF₃ —> C₇F₁₆ + 16HF + 32CoF₂

Explanation:

C₇H₁₆ + CoF₃ —> C₇F₁₆ + HF + CoF₂

The above equation can be balance as illustrated below:

C₇H₁₆ + CoF₃ —> C₇F₁₆ + HF + CoF₂

There are 16 atoms of H on the left side and 1 atom on the right side. It can be balance by writing 16 before HF as shown below:

C₇H₁₆ + CoF₃ —> C₇F₁₆ + 16HF + CoF₂

There are 3 atoms of F on the left side and a total of 34 atoms on the right side. It can be balance by writing 32 before CoF₃ and 32 before CoF₂ as shown below:

C₇H₁₆ + 32CoF₃ —> C₇F₁₆ + 16HF + 32CoF₂

Now, the equation is balanced.

3 0
3 years ago
The three main groups of elements are metals, nonmetals, and
Sedbober [7]

Answer:

Metalloids

Explanation:

.... .....................

4 0
3 years ago
How fast must a 56.5-g tennis ball travel in order to have a de Broglie wavelength that is equal to that of a photon of green li
nikklg [1K]

Answer:vv

v=2.17\times 10^{-26}\ m/s

Explanation:

The expression for the deBroglie wavelength is:

\lambda=\frac {h}{m\times v}

Where,  

\lambda is the deBroglie wavelength  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

m is the mass of = 56.5\ g=0.0565\ kg

v is the speed.

Wavelength = 5400 Å = 5400\times 10^{-10}\ m

Applying in the equation as:-

5400\times 10^{-10}=\frac{6.626\times 10^{-34}}{0.0565\times v}

v=\frac{331300000}{10^{34}\times \:1.5255}\ m/s

v=2.17\times 10^{-26}\ m/s

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