Answer:
O(Oxygen)
Explanation:
Oxygen or O among the given options has the highest electronegativity of 3.5 as compared to 2.4 of sulfur. Thus, there is a lesser attraction in the bonds of Sulfur. <u>The other two elements Al(Aluminium) and Cu are less electronegative than Sulfur and Oxygen as they are metals and possess electropositivity while the latter displays more electronegativity due to being non-metals</u>. Hence, Oxygen is the answer.
KCl2 (potassium dichloride) ?I’m not completely sure
When products form in an exergonic reaction, the <span>energy required to break bonds is less than the energy released from new bonds. This is usually given off as light. I hope this is the answer you are looking for. Looking forward to help you again. Have a great day ahead!</span>
Answer: ![K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3Cl%5D%5Ctimes%20%5BOH%5E-%5D%7D%7B%5BCH_3OH%5D%5Ctimes%20%5BCl%5E-%5D%7D)
Explanation:
Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients. Pure solids are assumed to have a concentration of 1.
The given balanced equilibrium reaction is:

The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3Cl%5D%5Ctimes%20%5BOH%5E-%5D%7D%7B%5BCH_3OH%5D%5Ctimes%20%5BCl%5E-%5D%7D)
Thus the equilibrium constant expression for this reaction is ![K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3Cl%5D%5Ctimes%20%5BOH%5E-%5D%7D%7B%5BCH_3OH%5D%5Ctimes%20%5BCl%5E-%5D%7D)