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Airida [17]
2 years ago
10

What is the necessary voltage to power the electrolysis of molten sodium chloride?

Chemistry
1 answer:
sammy [17]2 years ago
6 0

4V  is the necessary voltage to power the electrolysis of molten sodium chloride.

To create sodium metal and chlorine gas, molten (liquid) sodium chloride can be electrolyzed. A Down's cell is the name of the electrolytic cell utilised in the procedure. The liquid sodium ions in a Down's cell are converted to liquid sodium metal at the cathode. Liquid chlorine ions are oxidised to chlorine gas at the anode. Below is an illustration of the reactions and cell potentials:

oxidation: 2Cl^{-} (l) → Cl_{2} (g) + 2e^{-}                                  E°= -1.36V

reduction: Na^{+} (l) + e^{-} → Na (l)                                    E°= -2.71V

overall : 2Na^{+} (l) + 2Cl^{-} (l) → 2Na(l) +Cl_{2} (g)              E°_{cell} = -4.07V

For this electrolysis to take place, the battery needs to supply more than 4 volts. The only means to obtain pure sodium metal is by this reaction, which also serves as a significant source of chlorine gas generation. Swimming pools and other surfaces are frequently cleaned and disinfected with chlorine gas.

Learn more about sodium chloride here;

brainly.com/question/9811771

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Which scenario supports the ""one gene–one enzyme"" hypothesis of metabolic disease causation?
damaskus [11]

The scenario that supports the "one gene-one enzyme" hypothesis of metabolic disease causation is Phenylketonuria (PKU). This disease (PKU) is caused by the failure to produce a functional variant of an enzyme.

Phenylketonuria (PKU) is a metabolic inherited disorder associated with a decreased metabolism of the amino acid phenylalanine.

PKU is caused by a mutation in the gene responsible for encoding a key enzyme needed to break down phenylalanine.

Untreated PKU may lead to diverse health problems which include brain damage, intellectual disability, seizures, mental disorders, etc.

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4 0
2 years ago
A sample of hydrogen gas at a pressure of 0.926 atm and a temperature of 29.5 C, occupies a volume of 457 mL. If the gas is allo
klio [65]

Answer:

V₂ = 946.72 mL

Explanation:

Given data;

Initial pressure = 0.926 atm

Initial volume = 457 mL

Temperature = constant = 29.5°C

Final pressure = 0.447 atm

Final volume = ?

Solution:

The given problem will be solved through the Boyle's law,

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

by putting values,

P₁V₁ = P₂V₂

0.926 atm × 457 mL = 0.447 atm × V₂

V₂ = 423.18 atm. mL/ 0.447 atm

V₂ = 946.72 mL

4 0
2 years ago
Write the cell notation for the voltaic cell that incorporates each of the following redox reactions:(a) Al(s) + Cr³⁺(aq) → Al³⁺
Sladkaya [172]

The cell notation for the given voltaic cell is as follows

Al(s) | Al³⁺(aq) || Cr³⁺ (aq) | Cr(s)

<h3>What is a voltaic cell?</h3>

The device in which electrons are transferred through an external source is known as a voltaic cell.

The electron flow of a Voltaic cell allows redox reactions to produce energy in the form of electricity.

It converts the energy of spontaneous redox reaction into electrical energy

An anode, a cathode, and a salt bridge are all parts of a voltaic cell's setup. The salt bridge serves to neutralize the system.

To write the cell notation, identify the oxidation and reduction reactions.

At the anode, oxidation takes place

Al(s) \longrightarrow Al^{3+} (aq) + 3e^-

At the cathode, reduction takes place

Cr^{3+} (aq) + 3e^- \longrightarrow Cr(s)

While writing cell notation, the anode is written on the left, and the cathode is written on the right

A single vertical line differentiates between the phases and a double vertical line represents the salt bridge.

Now, write the cell notation of the given Voltaic cell

Al(s) | Al³⁺(aq) || Cr³⁺ (aq) | Cr(s)

Learn more about Voltaic cells:

brainly.com/question/14312871

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7 0
2 years ago
g, Assuming the precipitate is totally insoluble in water, which aqueous ions will be present in the solution (collected in the
Allushta [10]

Answer:

Cl⁻, Na⁺, OH⁻

Explanation:

The titration is:

CuCl₂(aq) + 2 NaOH(aq) → Cu(OH)₂(s) + 2 NaCl(aq)

In solution, before the reaction, the ions are Cu²⁺ and Cl⁻. The addition of NaOH (Na⁺ + OH⁻) produce the precipitation of Cu²⁺ forming Cu(OH)₂(s). When you reach the equivalence point, there is no Cu²⁺ because precipitates completely. All OH⁻ ions reacts when are added but when Cu²⁺ is finished, excess OH⁻ ions still in solution helping to detect the equivalence point.

Thus, ions present after the equivalence point are:<em> Cl⁻, Na⁺</em> (Don't react, spectator ions), and <em>OH⁻</em>.

3 0
3 years ago
Help please all please
Luden [163]

Answer:

I don’t want to download a pdf that I don’t know what it is…

Also, brainly strictly says that we can’t post questions about a test or quiz that is found in school…

Explanation:

5 0
3 years ago
Read 2 more answers
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