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Airida [17]
2 years ago
10

What is the necessary voltage to power the electrolysis of molten sodium chloride?

Chemistry
1 answer:
sammy [17]2 years ago
6 0

4V  is the necessary voltage to power the electrolysis of molten sodium chloride.

To create sodium metal and chlorine gas, molten (liquid) sodium chloride can be electrolyzed. A Down's cell is the name of the electrolytic cell utilised in the procedure. The liquid sodium ions in a Down's cell are converted to liquid sodium metal at the cathode. Liquid chlorine ions are oxidised to chlorine gas at the anode. Below is an illustration of the reactions and cell potentials:

oxidation: 2Cl^{-} (l) → Cl_{2} (g) + 2e^{-}                                  E°= -1.36V

reduction: Na^{+} (l) + e^{-} → Na (l)                                    E°= -2.71V

overall : 2Na^{+} (l) + 2Cl^{-} (l) → 2Na(l) +Cl_{2} (g)              E°_{cell} = -4.07V

For this electrolysis to take place, the battery needs to supply more than 4 volts. The only means to obtain pure sodium metal is by this reaction, which also serves as a significant source of chlorine gas generation. Swimming pools and other surfaces are frequently cleaned and disinfected with chlorine gas.

Learn more about sodium chloride here;

brainly.com/question/9811771

#SPJ4

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From the statement, we can see that the person is not too sure of the information provided since he "thinks". <em>He said, </em><em>"I think</em><em> that between an elephant and a monkey that jumped off the cliff, both of them will hit the ground at the same time." </em>

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Hence we can conclude that the person is stating a hypothesis.

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A sample of pure NO2 is heated to 335 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+
vodka [1.7K]

The equilibrium constant for the reaction is 0.00662

Explanation:

The balanced chemical equation is :

2NO2(g)⇌2NO(g)+O2(g

At t=t  1-2x ⇔ 2x + x moles

The ideal gas law equation will be used here

PV=nRT

here n= \frac{w}{W} = \frac{w}{V}= density

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putting the values in reaction

0.75 = \frac{0.525 x 0.0821 x 608.15 }{M}

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to calculate the Kc

Kc=\frac{ [NO] [O2]}{NO2}

  \frac{1-2x}{1+x} x M NO2 + \frac{2x}{1+x} M NO+ \frac{x}{1+x} M O2

Putting the values as molecular weight of NO2, NO,O2

\frac{46(1-2x) +30(2x)+32x}{1+x}

34.61= \frac{46}{1+x}

x= 0.33

Kc= \frac{4x^2)x}{1-2x^2}

    putting the values in the above equation

Kc = 0.00662

     

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