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tia_tia [17]
3 years ago
6

Calculate the following:

Chemistry
1 answer:
Brrunno [24]3 years ago
4 0

Follow these steps to solve the given equation:

Multiply the two decimal figures together and find the sum of the exponents, that is,

(1.5 * 1.89) * 10 ^4+3

(2.835) * 10^7

10^7 can also be written as e.70

'e' stands for exponential. 

Therefore, we have  2. 835 e 7.0 = 2.8 e 7.0.

Based on the calculations above, the correct option is A. 

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Identify the molecules or ions below as Lewis acids, Lewis bases, or neither. If there is more than one possible site in the mol
Varvara68 [4.7K]

Answer:

This question is incomplete because of the absence of the molecules been referred to in the question. However, the molecules been referred to in the question is in the attachment below

Explanation:

First of all, we have to define lewis acid and lewis base.

A lewis acid is a substance that has the capacity to accept a pair of electrons. For example, H⁺. While a lewis base is a substance that is capable of donating a pair of electrons (to a lewis acid). For example, OH⁻.

Going by the definitions above, we can deduce the type of substance the molecules in the question (attachment) are

a. BF₃ (boron trifluoride) is a lewis acid because the central atom (as suggested to be focused on in the question) which is <u>boron, has the capacity to accept a pair of electrons</u>.

b. The central atom (carbon) in the compound (2-methyl propane) <u>also has the capacity to accept a pair of electrons</u> since it is positively charged (is electron deficient). Hence, it is a lewis acid.

c. The functional group in this compound (trimethyl borate) is the ether. Ethers are generally lewis bases because the oxygen atom in an ether can donate a pair of electrons from it's lone pair. However, the <u>presence of boron which is central to the compound</u> shows it is also a lewis acid, although weak (majorly due to the presence of the ethers).

8 0
3 years ago
Scoring Scheme: 3-3-2-1 Use one of your experimentally determined values of k, the activation energy you determined, and the Arr
Lena [83]

Answer:

K = 2.7x10⁻⁵ at 25ºC

Explanation:

A way to write Arrhenius equation is:

ln K = - Ea/R × (1/T) + lnA

If you graph ln K as Y and 1/T as X (Absolute temperature in K), the equation you will obtain is:

Y = -13815X +35.817

R² = 0.9927

(Taking the last k point as 0.0386) (ln 0.0386), <em>0.1386 has no sense</em>)

Your slope is -13815

-13815K = - Ea/R

-13815K×8.314J/molK = 114858J/mol = Ea

And your intercept =

lnA = 35.817

A = 3.59x10¹⁵

Now, you want to know rate constant at 25ºC = 298.15K. Replacing in the equation (Where Y is ln (activation energy) and X is 1/T):

Y = -13815X +35.817

Y = -13815(1/298.15K) +35.817

Y = -10.5187

lnK = -10.5187

<h3>K = 2.7x10⁻⁵ at 25ºC</h3>

8 0
3 years ago
“The chemical formula in the structure of phosphorus is shown below. This represents a(n)....”
den301095 [7]

Answer:

element made up of four (4) similar atoms.

Explanation:

An element is made up of one kind of atom. A compound is made up of 2 or more different kinds of atoms that are chemically together.

5 0
3 years ago
Determine the heat needed to warm 25.3 g of copper from 22 degrees celsius to 39 degrees celsius.
Serggg [28]

Answer:

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed  or heat lost

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

We have mass of copper = m = 25.3 g

Specific heat of copper = c = 0.385 J/g°C

ΔT  = 39°C - 22°C = 17°C

Heat absorbed by the copper :

Q=25.3 g\times 0.385 J/g^oC\times 17^oC=165.59 J

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

5 0
3 years ago
Could someone help pls ​
drek231 [11]
<h3>Solution-:</h3>

  • option D
  • maintains a constant volume.

#<em>o</em><em>f</em><em>f</em><em>i</em><em>c</em><em>a</em><em>i</em><em>l</em><em> </em><em>Nazo</em>

<em>ll </em><em>Radhe</em><em> Radhe</em><em> ll</em>

4 0
2 years ago
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