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Alexeev081 [22]
3 years ago
10

Which statement about these layers is accurate?

Chemistry
1 answer:
spayn [35]3 years ago
5 0

Answer:

i think option c is the answer

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How could you demonstrate boiling point?
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A light layer of vacuum grease is applied to the rim of the belljar. Water at room temperature is placed inside and the vacuum pump is then used to evacuate the vessel. When the air pressure is reduced to the vapour pressure of water at room temperature the water will begin to boil.

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3 years ago
What is the correct equilibrium constant
Ksju [112]

Answer:

(CO2)+(CF)/ (COF)².

Explanation:

k=

6 0
3 years ago
The _______ are found on the right side of the arrow in a chemical reaction. A. reactants B. products C. subscripts D. coefficie
julia-pushkina [17]

Answer:

B. products are found on the write side of the arrow in a chemical reaction.

8 0
3 years ago
Read 2 more answers
The hydrogen chloride (HCl) molecule has an internuclear separation of 127 pm (picometers). Assume the atomic isotopes that make
natta225 [31]

Answer:

the energy of the third excited rotational state \mathbf{E_3 = 16.041 \ meV}

Explanation:

Given that :

hydrogen chloride (HCl) molecule has an intermolecular separation of 127 pm

Assume the atomic isotopes that make up the molecule are hydrogen-1 (protium) and chlorine-35.

Thus; the reduced mass μ = \dfrac{m_1 \times m_2}{m_1 + m_2}

μ = \dfrac{1 \times 35}{1 + 35}

μ = \dfrac{35}{36}

∵ 1 μ = 1.66 × 10⁻²⁷ kg

μ  = \\ \\ \dfrac{35}{36} \times 1.66 \times 10^{-27} \ \  kg

μ  = 1.6139 × 10⁻²⁷ kg

r_o = 127 \ pm = 127*10^{-12} \ m

The rotational level Energy can be expressed by the equation:

E_J = \dfrac{h^2}{8 \pi^2 I } \times J ( J +1)

where ;

J = 3 ( i.e third excited state)  &

I = \mu r^2_o

E_J= \dfrac{h^2}{8  \pi  \mu r^ 2 \mur_o } \times J ( J +1)

E_3 = \dfrac{(6.63 \times 10^{-34})^2}{8  \times  \pi ^2  \times 1.6139 \times 10^{-27} \times( 127 \times 10^{-12}) ^ 2  } \times 3 ( 3 +1)

E_3= 2.5665 \times 10^{-21} \ J

We know that :

1 J = \dfrac{1}{1.6 \times 10^{-19}}eV

E_3= \dfrac{2.5665 \times 10^{-21} }{1.6 \times 10^{-19}}eV

E_3 = 16.041  \times 10 ^{-3} \ eV

\mathbf{E_3 = 16.041 \ meV}

8 0
2 years ago
How were the elements in the first periodic table arranged?
Snezhnost [94]

Based on atomic mass

Explanation:

Elements were arranged on the first periodic table based on their atomic masses.

The mass of an atom is made up of the mass of the nucleus which contains the protons and neutrons.

  • Dimitri Mendeleev was the first person credited for arranging elements periodically.
  • He was said to have been inspired while playing his game of solitaire on a train.
  • On his table, he left spaces for the atomic masses of elements not yet discovered.
  • Today, the periodic table is based on the atomic numbers of elements. This is the number of protons in an atom.

Learn more:

Periodic table brainly.com/question/2690837

#learnwithBrainly

5 0
3 years ago
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