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Makovka662 [10]
3 years ago
6

In the Lewis structure of BF3, how many lone pairs surround the boron atom?

Chemistry
2 answers:
7nadin3 [17]3 years ago
7 0

Answer:

A 0

Explanation:

aev [14]3 years ago
7 0
The answer is a.0,

Explanation: Boron trifluoride only has six valence electrons. There are three bonded groups and so no lone pairs. Six electrons implies three electron pairs and therefore a trigonal geometry.
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Which element has the element configuration 1s2 2s2 2p4
expeople1 [14]

Answer:

O(Oxygen)

Explanation:

2+2+4=8

And the eighth element of the periodic table is Oxygen

3 0
3 years ago
An inverse relationship can be represented by:<br> a straight line<br> a bar chart
kolezko [41]

Answer:

An inverse relationship can neither be represented by a straight line nor by a bar chart. But it can be represented by "xy = k"

Explanation:

                   Inverse relation is used for the values which are inversely related to each other. For example: Let suppose you have a value x and y. Then an increase in the value of x will result in the decrease of value y. Mathematically it is represented as,

                                                         x  ∝  1 / y

Where;

              ∝ = proportionality

Replacing the proportionality sign by a constant value "k" the relation becomes,

                                                         x  =  k / y

Solving for k,

                                                         x y  =  k

Conclusion:

                  Hence, an inverse relationship can be represented by "xy = k"

7 0
3 years ago
Read 2 more answers
Balance this equation and determine what the coefficients should be.
11Alexandr11 [23.1K]

Answer:

1, 2, 1, 1

Explanation:

3 0
3 years ago
Draw a schematic diagram of a circuit with an output device, a energy source and a controller.
mart [117]

Answer:

ch∪pαpi munαn0?

Explanation:

8 0
3 years ago
Calculate the work done when an ideal gas expands isothermally and reversibly in a piston and cylinder assembly for expansion of
pantera1 [17]

Answer:

W=5743.1077\ J

Explanation:

The expression for the work done is:

W=RT \ln \left( \dfrac{P_1}{P_2} \right)

Where,

W is the amount of work done by the gas

R is Gas constant having value = 8.314 J / K mol

T is the temperature

P₁ is the initial pressure

P₂ is the final pressure

Given that:

T = 300 K

P₁ = 10 bar

P₂ = 1 bar

Applying in the equation as:

W=8.314\times 300 \ln \left( \dfrac{10}{1} \right)

W=300\times \:8.314\ln \left(10\right)

W=2.30258\times \:2494.2

W=5743.1077\ J

5 0
3 years ago
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