C. The membrane is inside the cell wall. The cell wall surrounds the membrane.
Answer:
346819 Pa or ,347000 Pa in 3 significant figures
Explanation:
P1= 325000Pa , T1= 283K ,
P2=? T1= 302 K
as here volume and mass both are constant so using ratio method for pressure temperature law we have P1/T1 = P2/T2
THIS WE CAN ALSO OBTAIN BY RATIO METHOD FOR GENERAL GAS LAW AS
P1V1/(m1T1 ) = P2 V2/ (m2 T2)
IF V1 = V2 =V AND m1=m2=m then expression reduces to
P1/T1 = P2/T2
or P2 = (P1/T1)×T2
P2 = (325000/283) × 302
P2 = 1148.41×302
P2=346819
P2 = 347000 Pa in 3 significant figures
D. they have a full luster
366J. Energy is conserved and is transformed from completely potential energy at the top to completely kinetic at the bottom.
image distance,di=10 cm
object distance,do=20cm
magnification, m=di/do
=10/20
=0.5
since the image is virtual, magnification is negative.
therefore m=-0.5
