Answer:
According to Kepler's 3rd law.
It states that the orbital period, T is related to the distance, r as:
T²
= 4
π²r³
/G M
where G is the universal gravitational constant = 6.673 × 10⁻¹¹ Nm²/kg²
Rearranging for M should give Jupiter's mass.
M =
4
π²r³/GT²
T= 1.77 days × 24 h/day × 60 min/h × 60 s/min = 1.53 × 10⁵ s
r = 4.22x10⁸ m
M = 4π² ((4.22 × 10⁸ m)³/(6.673 × 10⁻¹¹ Nm²/kg² x (1.53 × 10⁵ s)²)
M = 1.90 × 10²⁷kg
The mass of Jupiter is 1.90 × 10²⁷kg.
1.90 × 10²⁷kg
T= 7.16 days × 24 h/day × 60 min/h × 60 s/min = 6.19 × 10⁵s
r = 1.07x10⁹ m
M = 4π² ((1.07 × 10⁹ m)³/(6.673 × 10⁻¹¹ Nm²/kg² x (6.19 × 10⁵ s)²)
M = 1.90 × 10¹⁷kg
The mass of Jupiter is 1.90 × 10¹⁷kg.
THE RESULTS TO PART A and B ARE NOT CONSISTENT. The reason is because of the difference in radius of each satellites from Jupiter. i.e the farther away the moons, the smaller they become in space and the more the number of days to complete an orbit.
As per conditions described here we know that all force arrow are not of equal length
So all forces are not same in magnitude
Here applied force on right direction is more in magnitude then the friction force on left
So it will have net unbalanced force towards right due to which it will move towards right direction or in the direction of net unbalanced force
While in the upward and downward direction the forces are balanced and hence the box will not move in that direction
So normal force will be balanced by gravitational force
So here answer will be
The forces acting on the box are <u>UNBALANCED</u> .
The box will move to the <u>RIGHT</u> .
