Answer:
The limiting reactant is the copper
Explanation:
Moles are the standard unit at which you can compare values, and copper has fewer moles than Silver nitrate, so in a reaction, it would be used up first, leaving Silver nitrate in excess.
Answer:
<h3><em>What is filteration</em><em>:</em></h3>
Filtration, the process in which solid particles in a liquid or gaseous fluid are removed by the use of a filter medium that permits the fluid to pass through but retains the solid particles. ... In some processes used in the production of chemicals, both the fluid filtrate and the solid filter cake are recovered.
<h3><em>When</em><em> </em><em>do</em><em> </em><em>we</em><em> </em><em>use</em><em> </em><em>it</em><em>:</em></h3>
<em>Filtration is used to separate particles and fluid in a suspension, where the fluid can be a liquid, a gas or a supercritical fluid. Depending on the application, either one or both of the components may be isolated.</em>
<h3><em>In</em><em> </em><em>order</em><em> </em><em>to</em><em> </em><em>separate</em><em> </em><em>a</em><em> </em><em>salt-water</em><em> </em><em>mixture</em><em>,</em></h3><h3><em>should</em><em> </em><em>a</em><em> </em><em>student</em><em> </em><em>use</em><em> </em><em>filtration</em><em>:</em></h3>
The mixture can be separated by filtration, by dissolving the mixture in water. Salt will dissolve in the water, whereas sand will not.
Explanation:
<h3>hope it help's. pls mark as the brainliest.Rocket out.</h3>
Answer:
Explanation:
An atom on a face is shared by two unit cells, so only half of the atom belongs to each of these cells. An atom on an edge is shared by four unit cells, and an atom on a corner is shared by eight unit cells.
Answer:- Volume of the gas in the flask after the reaction is 156.0 L.
Solution:- The balanced equation for the combustion of ethane is:

From the balanced equation, ethane and oxygen react in 2:7 mol ratio or 2:7 volume ratio as we are assuming ideal behavior.
Let's see if any one of them is limiting by calculating the required volume of one for the other. Let's say we calculate required volume of oxygen for given 36.0 L of ethane as:

= 126 L 
126 L of oxygen are required to react completely with 36.0 L of ethane but only 105.0 L of oxygen are available, It means oxygen is limiting reactant.
let's calculate the volumes of each product gas formed for 105.0 L of oxygen as:

= 60.0 L 
Similarly, let's calculate the volume of water vapors formed:

= 90.0 L 
Since ethane is present in excess, the remaining volume of it would also be present in the flask.
Let's first calculate how many liters of it were used to react with 105.0 L of oxygen and then subtract them from given volume of ethane to know it's remaining volume:

= 30.0 L 
Excess volume of ethane = 36.0 L - 30.0 L = 6.0 L
Total volume of gas in the flask after reaction = 6.0 L + 60.0 L + 90.0 L = 156.0 L
Hence. the answer is 156.0 L.