A calibration curve requires the preparation of a set of known concentrations of CV, which are usually prepared by dieting a stock solution whose concentration is known.
Answer:
0.208mole of CO2
Explanation:
First, let us calculate the number of mole of HC3H3O2 present.
Molarity of HC3H3O2 = 0.833 mol/L
Volume = 25 mL = 25/100 = 0.25L
Mole =?
Mole = Molarity x Volume
Mole = 0.833 x 0.25
Mole of HC3H3O2 = 0.208mole
Now, we can easily find the number of mole of CO2 produce by doing the following:
NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2
From the equation,
1mole of HC2H3O2 produced 1 mole of CO2.
Therefore, 0.208mole of HC2H3O2 will also produce 0.208mole of CO2
Answer:
I think B
Explanation:
There are more negative ions than positive ions
Answer:
The emmision of ionizing radiation or particles caused by the spontaneous disintegration of atomic nuclei
or
the giving off of rays of energy or particles by the breaking apart of atoms of certain elements
Answer:
T = 3206.89 K
Explanation:
Given that,
Number of moles, n = 1.9 moles
Pressure, P = 5 atm
Volume, V = 100 L
We need to find the temperature of the gas. Let the temperature is T. We know that,
PV = nRT
Where
R is gas constant, R = 0.08206 L-atm/mol-K
Put all the values,
So, the temperature of the gas is 3206.89 K.
