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o-na [289]
4 years ago
6

1. What causes water's low vapor pressure? (1 point)

Chemistry
1 answer:
arsen [322]4 years ago
5 0
<span>1. What causes water's low vapor pressure? (1 point)
dispersion forces
dispersion forces
covalent bonding
hydrogen bonding
ionic attractions
2. Which of the following substances is the most soluble in water? (1 point)
sodium chloride
methane
bromine
carbon
3. Which of the following substances is NOT an electrolyte? (1 point)
KCl
CCl4
LiCl
Na2SO4
4. Which of the following mixture types can be filtered to remove solute? (1 point)
suspensions only
colloids only
suspensions and colloids
suspensions and solutions
5. Which of the following mixtures is NOT a colloid? (1 point)
fog
milk
paint
sugar water
6. Which of the following types of mixtures exhibit the Tyndall effect? (1 point)
suspensions and colloids
suspensions and solutions
colloids and solutions
colloids only
7. An emulsyfying agent is typically characterized by having ____. (1 point)
one polar end
one nonpolar end
one nonpolar end
two polar ends
one polar end and one nonpolar end</span>
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Natalka [10]

Answer: (a) Mole fraction of H_{2} is 0.66.

Mole fraction of N_{2} is 0.33

(b) The partial pressure of H_{2} is 1.98 atm.

The partial pressure of N_{2} is 0.99 atm.

(c) The total pressure is 3.0 atm

Explanation:

Given: Volume = 22.4 dm^{3}  (1 dm^{3} = 1 L) = 22.4 L

Moles of H_{2} = 2.0 mol

Moles of N_{2} = 1.0 mol

Total moles = (2.0 + 1.0) mol = 3.0 mol

Temperature = 273.15 K

  • Now, using ideal gas equation the total pressure is calculated as follows.

PV = nRT\\

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\P \times 22.4 L = 3.0 mol \times 0.0821 L atm/mol K \times 273.15 K\\P = 3.0 atm

  • The mole fractions of each component:

The mole fraction of H_{2} is calculated as follows.

Mole fraction = \frac{moles of H_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{2.0 mol}{(2.0 + 1.0) mol}\\= 0.66

The mole fraction of N_{2} is as follows.

Mole fraction = \frac{moles of N_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{1.0 mol}{(2.0 + 1.0) mol}\\= 0.33

  • The partial pressures of each component:

Partial pressure of H_{2} are as follows.

P_{H_{2}} = P_{total} \times mole fraction of H_{2}\\= 3.0 atm \times 0.66\\= 1.98 atm

Partial pressure of N_{2} are as follows.

P_{N_{2}} = P_{total} \times mola fraction of N_{2}\\= 3.0 atm \times 0.33\\= 0.99 atm

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