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2 years ago

Identify the types of chemical reactions occurring in the chemical Quetion‘s.

Chemistry

1 answer:

Bogdan [553]2 years ago

4 0

Combination reaction

In this reaction two or more reactants combine with each other to form a single product

Decomposition reaction

In this reaction one reactant is decomposed into two or more products

Displacement reaction

In this reaction higher reactive element displaces lower reactive element from its solution

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What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?

mars1129 [50]

The concentration of solution in M or mol/L can be calculated using the following formula:

$C=\frac{n}{V}$ .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is $K_{2}SO_{4}$ thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

$n=\frac{m}{M}$

Here, m is mass and M is molar mass

Putting the values,

$n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol$

Thus, number of moles of $K_{2}SO_{4}$ will be $0.1061\times 0.5=0.053 mol$ .

The volume of solution is 225 mL, converting this into L,

$1 mL=10^{-3}L$

Thus,

$225 mL=0.225 L$

Putting the values in equation (1),

$C=\frac{(0.053 mol}{0.225 L}=0.236 M$

Therefore, concentration of potassium sulfate solution is 0.236 M.

4 0

3 years ago

Throughout the reflection, make sure you have a copy of the Student Guide and your data tables. Use the drop-

Inessa05 [86]

Answer:

1) mass and type of material

2) type of material

3) temperature

Explanation:

8 0

2 years ago

The decomposition of formic acid follows first-order kinetics. HCO2H(g) → CO2(g) + H2(g) The half-life for the reaction at 550°C

FromTheMoon [43]

Answer:

Option 4 is correct (72 seconds)

Explanation:

Option 4 is correct (72 seconds)

The formula we are going to use is:

$ln\frac{A}{A_o}=-kt$

Where:

A is the final concentration

A_o is the initial concentration

k is the constant

t is the time

Half-Life=0.693/k

Half-life in our case=24 seconds

k=0.693/24

k=0.028875 s^-1

Since the concentration is decreased by 87.5 % which means only 12.5%(100-87.5%) is left.

The ratio $A/A_o$ will become 0.125

$ln 0.125=-0.028875*t\\t=72.015\ seconds$

t≅ 72 seconds

5 0

3 years ago

The type of reaction represented by the following equation is...

tatiyna

Answer:

I think it's C but I'm atlessy 60% sure :]

7 0

3 years ago

How many moles are in 23.8 g of sulfur dioxide

Yuki888 [10]

Answer:

0.371

Explanation:

number of moles = mass / Ar

= 23.8g / 32.1 + (16.0 × 2)

= 0.37129485179 = 0.371 (3 s.f).

hope it helps :)

4 0

2 years ago