Answer:
Some of the orbits are nearly circular, while the moons farthest from Jupiter have more irregular orbits. The outer moon's orbit in the opposite direction in which Jupiter spins, which is unusual and indicates the moons were asteroids that were sucked into Jupiter's orbit after the initial system was formed.
Explanation:
The electronic transition that will produce the lowest frequency is an electron falling from the 3rd to the 2nd energy level.
The question is incomplete, the complete question is;
As electrons fall from high energy orbitals to lower orbitals, energy is released in the form of electromagnetic radiation. The farther the electron falls, the more energy is released. Which of the following electronic transitions would produce a wave with the lowest frequency?
an electron falling from the 6th to the 2nd energy level
an electron falling from the 5th to the 2nd energy level
an electron falling from the 3rd to the 2nd energy level
an electron jumping from the 1st to the 2nd energy level
According to Bohr's theory, energy is absorbed or emitted when an electron moves from one energy level to another. This energy often occurs as visible light of known frequency and wavelength.
The magnitude of frequency of light depends on the difference in energy between the two energy levels. If the difference between the energy levels is high, the frequency of light is also high and vice versa.
The transition from 3rd to the 2nd energy level represents a low frequency transition because the energy levels are close together.
Learn more: brainly.com/question/10675485
Ionic bond is a chemical bond formed by the complete transfer of electrons between two atoms. The atom that loses electrons gains a positive charge (cation) and that which accepts electrons gains a negative charge (anion). Now, electronegativity is a parameter that measures the tendency of an atom to accept electrons. In the context of ionic bonding, two elements which show a significant difference in their electronegativity values form ionic bonds.
In the given examples, the difference in electronegativity is greatest between K and Br i.e. 0.8 and 2.8 respectively with a difference of 2.0. This also makes sense since K and Br are on the extreme ends of the periodic table. Hence, potassium with a valence electron configuration of 4s1 will lose its s electron to Br (4s24p6) and form an ionic molecule K⁺Br⁻
Ans E) potassium and bromine
He was working with electrons
