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Tcecarenko [31]
3 years ago
7

How many moles are in 8.30x10^23 molecules of H2o

Chemistry
2 answers:
sasho [114]3 years ago
8 0

Answer: 1.38 moles

Explanation: According to Avogadro's law, 1 mole of every substance contains Avogadro number of particles (atoms, molecules or ions) i.e. 6.023\times 10^{23} particles.

Given : 1 mole molecule of water contains 6.023\times 10^{23} molecules of water.

6.023\times 10^{23} molecules are present in = 1 mole

8.30\times 10^{23}  molecules will be present in =\frac{1}{6.023\times 10^{23}}\times 8.30\times 10^{23}=1.38 moles

Thus 8.30\times 10^{23} molecules is equal to 1.38 moles.

LUCKY_DIMON [66]3 years ago
4 0
You multiply avogadro's number to what you were given.
8.30x10^23 * 6. 0221409x10^23
=1.357*10^25

That should be the right answer but I'm not sure. It has been awhile since I have done this.

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The elements from this section of the periodic table all belong to the same
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Answer:

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Electronic configuration of neon:

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All these elements present in same period having same electronic shell.

However their families, valance electrons and group are different. Boron have three valance electrons and belongs to group 3A. Carbon belongs to group 4A and have 4 valance electrons. Nitrogen belongs to group 5A and have five valance electrons. Oxygen belongs to group 6A and have six valance electrons. Fluorine belongs to group 7A and have seven valance electrons.

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Answer:

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Explanation:

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