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3 years ago

11

A cylinder contains 12liters of O2 at 20°c and 15atm. The temperature is raised to 35°c and volume is reduced to 8.5L. Calculate

the final pressure. What will be the new pressure if the volume is doubled

1 answer:

svet-max [94.6K]3 years ago

5 0

<h2>Pressure : 11 atmosphere</h2>

Explanation:

According to gas equation P₁V₁/T₁ = P₂V₂/T₂

Where P₁ is the initial pressure , V₁ is the initial volume and T₁ is the initial temperature

P₂ is the final pressure , V₂ is the final volume and T₂ is the final temperature

Thus P₁ = 15 atmosphere , V₁ = 12 liters and T₁ = 273 + 20 = 293 K

P₂ = ? , V₂ = 8.5 liters , T₂ = 273 + 35 = 308 K

From gas equation P₂ = P₁V₁T₂/T₁V₂ = 15 x 12 x 308/ 293 x 8.5

= 22.3 atmosphere .

If the volume is doubled

The gas equation will be P₁V₁ = P₂V₂ ; because temperature is constant

Here V₂ = 2 V₁ therefore pressure P₂ = P₁/2 = 22.3/2 = 11.1 atmosphere

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For this problem, we just need to remember conservation of momentum, as there are no external forces in the horizontal direction:

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So, our velocity vectors will be:

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