Answer:
If we consider a system where the y-axis as the South-North line, and the x-axis as the West-East line (where North and East are the positive sides)
We know that the sun goes from East to West, so in our system, the sun goes from the positive side of the x-axis to the negative side of the x-axis.
Where we would see this if we were standing right in the equator line.
If we where in other point of the planet, the Sun will stil move from East to West, but it will have a little tilt along the path, so we will have a little displacement in the y-axis. This displacement will depend on where we are, if we are at the North of the equator, we will se that the sun seems to go a little towards South as it goes to the West side.
Answer:
θ = 6.3 *10³ revolutions
Explanation:
Angular acceleration of the drill
We apply the equations of circular motion uniformly accelerated
ωf= ω₀ + α*t Formula (1)
Where:
α : Angular acceleration (rad/s²)
ω₀ : Initial angular speed ( rad/s)
ωf : Final angular speed ( rad
t : time interval (s)
Data
ω₀ = 0
ωf = 350000 rpm = 350000 rev/min
1 rev = 2π rad
1 min= 60 s
ωf = 350000 rev/min =350000*(2π rad/60 s)
ωf = 36651.9 rad/s
t = 2.2 s
We replace data in the formula (2) :
ωf= ω₀ + α*t
36651.9 = 0 + α* (2.2)
α = 36651.9 / (2.2)
α = 17000 rad/s²
Revolutions made by the drill
We apply the equations of circular motion uniformly accelerated
ωf²= ω₀ ²+ 2α*θ Formula (2)
Where:
θ : Angle that the body has rotated in a given time interval (rad)
We replace data in the formula (2):
(ωf)²= ω₀²+ 2α*θ
(36651.9)²= (0)²+ 2( 17000 )*θ
θ = (36651.9)²/ (34000 )
θ = 39510.64 rad = 39510.64 rad* (1 rev/2πrad)
θ = 6288.31 revolutions
θ = 6.3 *10³ revolutions
Is there supposed to an attachent like a pic or somthing?
Answer:
Stop cheating in exam
Explanation:
Shame!!!!
I am sorry but I will have to refer you to the student conduct at UTA.
