Answer:
(a) t = 0.75 s
(b) d = 26 m
Explanation:
Height, h = 12 m
Angle, A = 30 degree
initial velocity, u = 40 m/s
(a) Let the time is t.
Use second equation of motion
(b) d = u cos A t
d = 40 x cos 30 x 0.75 = 26 m
Answer:
Explanation:
Just start with the trivial. If gravity was a constant then E = mgh and 1/2 m v^2 = E
so v=sqrt(2gh)=sqrt(2*9.8*1590000) = 5582m/s
Now this will be too high as gravity reduces with distance.
However it is still true that 1/2mv^2 = loss of gravitational potential energy
so 1/2 v^2 = loss of gravitational potential ( i.e a field without considering mass )
As g = GM/ Ro^2 and P = - GM/R
the Po = - 9.8 * (6370*10^3)= - 62.4 * 10 ^ 6 J/kg
P1= Po * 6370/(6370+1590) = - 49.93 * 10 ^ 6 J/kg
find the CHANGE and then from that the velocity
ie v = sqrt(2*( P1 - Po)) = 5094 m/s
Note how it is a bit smaller than the first estimate but not by such a margin that they are unrecognizably different.
Answer:
1) Because of the size and time the sound wave moves, an echo is typically transparent and easy to discern. Since reverberations typically don't have enough distance or time to fly, they will pile up on top of each other, making it impossible to understand.
People will detect an echo if the distance between the source of the sound and the reflected body is greater than 50 feet. When a sound wave is bounced off a nearby surface, it may create a reverberation.
2) The speed of sound in hot air is more than that in cold air because air molecules are traveling faster in hot air.
Explanation:
Answer:
21.6
Explanation:
0.6% * 36 = 21.6
are you looking for percentage or just answer??