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GuDViN [60]
3 years ago
8

What is NOT an example of Refraction. Remember to not give me an example.

Physics
1 answer:
MAXImum [283]3 years ago
7 0

There is reflection if that might work

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What method would produce disease resistant cattle in the shortest amount of time?
xenn [34]
My brother said it is D
7 0
3 years ago
A Capacitor is a circuit component that stores energy and can be charged when current flows through it. A current of 3A flows th
ddd [48]

Answer:

8\mu C

Explanation:

t = Time taken = 2\mu s

i = Current = 3 A

q(0) = Initial charge = 2\mu C

Charge is given by

q=\int_0^t idt+q(0)\\\Rightarrow q=\int_0^{2\mu s} 3dt+2\mu C\\\Rightarrow q=3(2\mu s-0)+2\mu C\\\Rightarrow q=6\mu C+2\mu C\\\Rightarrow q=8\mu C

The magnitude of the net electric charge of the capacitor is 8\mu C

4 0
3 years ago
You drag a suitcase of mass 8.2 kg with a force of f at an angle 41.9 ◦ with respect to the horizontal along a surface with kine
DedPeter [7]

Answer:

35.6 N

Explanation:

We can consider only the forces acting along the horizontal direction to solve the problem.

There are two forces acting along the horizontal direction:

- The horizontal component of the pushing force, which is given by

F_x = F cos \theta

with \theta=41.9^{\circ}

- The frictional force, whose magnitude is

F_f = \mu mg

where \mu=0.33, m=8.2 kg and g=9.8 m/s^2.

The two forces have opposite directions (because the frictional force is always opposite to the motion), and their resultant must be zero, because the suitcase is moving with constant velocity (which means acceleration equals zero, so according to Newton's second law: F=ma, the net force is zero). So we can write:

F_x - F_f=0\\F_x = F_f\\F cos \theta = \mu mg\\F=\frac{\mu mg}{cos \theta}=\frac{(0.33)(8.2 kg)(9.8 m/s^2)}{cos(41.9^{\circ})}=35.6 N

8 0
3 years ago
find a magnitude of the force such that if the act at right angle there resultant is √10N but if the act of 50° the resultant is
Readme [11.4K]

Explanation:

Let magnitude of the two forces be x and y.

Resultant at right angle R1= √15N) and at

60 degrees be R2= √18N.

Now, R1 = √(x² + y²) = √15,

R2= √(x² + y² +2xycos50) = √18.

So x² + y² = 15,

and x² + y² + 1.29xy = 18,

therefore 1.29xy = 3,

y = 3/1.29x.

y = 2.33/x

Now, x2 + (2.33/x)2 = 15,

x² + 5.45/x² = 15

multiply through by x²

x⁴ + 5.45 = 15x²

x⁴ - 15x2 + 5.45 = 0

Now find the roots of the equation, and later y. The two values of x will correspond to the

magnitudes of the two vectors.

Good luck

7 0
3 years ago
How many protons are in this atom if it has a balanced charge
Lerok [7]
It would be 20 protons left because 1-19= 20
7 0
2 years ago
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