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Marizza181 [45]
3 years ago
6

Name the net force between objects that allows a car to travel in a circle

Physics
1 answer:
iren [92.7K]3 years ago
6 0
I think centripetal force ☺
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D. used by the entire scientific community

B.  more accurate system of measurement

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Officials in the House of Representatives serve __ terms.
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Officials in the House of Representives have are able to serve a 2 year term and there are no limits as to how many terms.
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A worker uses a cart to move a load of bricks a distance of 10m across a parking lot. if he pushes the cart with a constant forc
andriy [413]

Answer:

2090 J

Explanation:

the work done to move the cart is equal to the product between the force applied and the distance traveled:

W=Fd

In this case, the force applied is F=209 N, while the distance covered is d=10 m, therefore the work done is

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In a transformer a 120 volt dc Primary of 500 turns is connected to a secondary of 75 turns. What is the Induced voltage in the
oee [108]

Answer:

The induced voltage in the Secondary is 18 volt.

Explanation:

Given that,

Voltage = 120 volt

Number of turns in primary = 500

Number of turns in secondary = 75

We need to calculate the induced voltage in the Secondary

Using relation number of turns and voltage in primary and secondary

\dfrac{V_{p}}{V_{s}}=\dfrac{N_{p}}{N_{s}}

Where, N_{p} = Number of primary coil

N_{s} = Number of  secondary  coil

V_{p} = Voltage of primary coil

V_{p} = Voltage of primary coil

Put the value into the formula

\dfrac{120}{V_{s}}=\dfrac{500}{75}

V_{s}=\dfrac{120\times75}{500}

V_{s}=18\ Volt

Hence, The induced voltage in the Secondary is 18 volt.

7 0
3 years ago
If it takes 32,000 joules of heat to warm 750 g of water, what was the temperature change?(the specific heat of water is 4.18 J/
Firdavs [7]

Answer:

10.21°C

Explanation:

From the question,we are given;

  • Quantity of heat = 32,000 Joules
  • Mass of water = 750 g
  • Specific heat capacity of water = 4.18 J/g°C

We are required to calculate the change in temperature;

  • We need to know that quantity of heat is calculated by multiplying mass by specific heat then by change in temperature.
  • That is;

Q = m × c × ΔT

Rearranging the formula;

ΔT = (Q ÷ (m × c))

     = 32,000 J ÷ (750× 4.18 J/g°C)

     = 10.21°C

Therefore, the change in temperature  is 10.21°C

7 0
3 years ago
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