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aleksklad [387]
4 years ago
5

A telephone line has a signal-to-noise ratio of 1000 and a bandwidth of 4 KHz. What is the maximum data rate supported by this l

ine?
Physics
1 answer:
ivolga24 [154]4 years ago
5 0

Answer:

The maximum data rate supported by this line is 39900 bps

Explanation:

The maximum data rate supported by this line can be obtained using the formula below

c = W*log2(S/N+1)

where;

c is the maximum data rate supported by the line

W is the bandwidth = 4kHz

S/N+1 is the signal to noise ratio = 1001

c = 4*log2(1001)

c = 39868.9 ≅ 39900 bps

Therefore, the maximum data rate supported by this line is 39900 bps

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A 0.76-kg block is hung from and stretches a spring that is attached to the ceiling. A second block is attached to the first one
sergey [27]

Answer:

1.54 kg

Explanation:

mass of first block (m) = 0.76 kg

acceleration due to gravity (g) = 9.8 m/s

what is the mass (m) of the second block

  • force = kx ⇒ mg = kx

        mg = kx

        where m is the mass, g is the acceleration due to gravity, k is the  

        spring constant and x is the extension

        0.76 x 9.8 = kx

       7.5 = kx

        k = 7.5/x ... equation 1

  • when a second block is attached to the first one the amount of stretch triples (this means that extension (x) = 3x)

        therefore the new mass becomes m + 0.76 and the extension  

        becomes 3x

        with the new mass and extension, mg = kx now becomes

        (m+0.76)g = k(3x) ... equation 2

        Recall that k = 7.5/x from equation 1, substituting this value of k into      

        equation 2 we have

         (m+0.76)g =  \frac{7.5}{x} × (3x)

         (m+0.76)g =  7.5 × 3

          substituting the value of g = 9.8 m/s^{2}

         (m + 0.76) x 9.8 = 7.5 x 3

          m + 0.76 = 22.5 ÷ 9.8

          m + 0.76 = 2.3

          m = 2.3 - 0.76 = 1.54 kg

       

         

       

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4 years ago
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Yes it does do all that
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A weather balloon has a volume of 90.0 l when it is released from sea level. What
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The final atmospheric pressure is 5.19\cdot 10^4 Pa

Explanation:

Assuming that the temperature of the air does not change, we can use Boyle's law, which states that for a gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume. In formula,

pV=const.

where

p is the gas pressure

V is the volume

The equation can also be rewritten as

p_1 V_1 = p_2 V_2

where in our problem we have:

p_1= 1.03\cdot 10^5 Pa is the initial pressure (the atmospheric pressure at sea level)

V_1 = 90.0 L is the initial volume

p_2 is the final pressure

V_2 = 175.0 L is the final volume

Solving the equation for p2, we find the final pressure:

p_2 = \frac{p_1 V_1}{V_2}=\frac{(1.01\cdot 10^5)(90.0)}{175.0}=5.19\cdot 10^4 Pa

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One way to describe a wave crest is the amount of ___________ applied over an area.
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