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Zanzabum
3 years ago
12

How much energy is needed to change the temperature of 50.0 g of water by 15.0oc?

Physics
1 answer:
UkoKoshka [18]3 years ago
3 0
The amount of energy needed to increase the temperature of a substance by \Delta T is given by:
Q=m C_s \Delta T
where
m is the mass of the substance
Cs is the specific heat capacity of the substance
\Delta T is the increase in temperature

In our problem, m=50.0 g, C_s = 4.18 J/g ^{\circ}C (specific heat capacity of water) and \Delta T=15.0 ^{\circ}C, therefore the amount of energy needed is
Q=mC_s \Delta T=(50.0 g)(4.18 J/g^{\circ}C)(15.0^{\circ}C)=3135 J
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igor_vitrenko [27]
The sentence can be completed as follows:
"<span>When more than one wave is in the same location at the same time, then there is interference between the waves"

In fact, when there are two or more waves in the same location at the same time, their amplitude sum together. The two extreme possibilities are:
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4 0
3 years ago
You find it takes 200 J of heat to take 4 kg of an unknown substance from 200 K to 240 K. It does not change phases during this
klasskru [66]

Answer:

300 K

Explanation:

First, we have find the specific heat capacity of the unknown substance.

The heat gained by the substance is given by the formula:

H = m*c*(T2 - T1)

Where m = mass of the substance

c = specific heat capacity

T2 = final temperature

T1 = initial temperature

From the question:

H = 200J

m = 4 kg

T1 = 200K

T2 = 240 K

Therefore:

200 = 4 * c * (240 - 200)

200 = 4 * c * 40

200 = 160 * c

c = 200/160

c = 1.25 J/kgK

The heat capacity of the substance is 1.25 J/kgK.

If 300 J of heat is added, the new heat becomes 500 J.

Hence, we need to find the final temperature, T2, when heat is 500 J.

Using the same formula:

500 = 4 * 1.25 * (T2 - 200)

500 = 5 * (T2 - 200)

100 = T2 - 200

=> T2 = 100 + 200 = 300 K

The new final temperature of the unknown substance is 300K.

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3 years ago
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3 0
3 years ago
Four objects are situated along the y axis as follows: a 2.09-kg object is at +2.97 m, a 2.93-kg object is at +2.53 m, a 2.57-kg
Tcecarenko [31]

Answer:

x = 0 m

y = 1.02 m

Explanation:

M1 = 2.09 kg

y1 = 2.97 m

M2 = 2.93 kg

y2 = 2.53 m

M3 = 2.57 kg

y3 = 0 m

M4 = 3.92 kg

y5 = -0.496 m

since all objects are situated on the Y-axis, this means the x coordinate of the center of mass is 0.

To find the y coordinate of the center of mass, we apply the equation below.

sum of moment of the objects about the origin = moment of the total mass of objects about the center of mass

M1.y1 + M2.y2 + M3.y3 + M4.y4 = Mt.Y

(2.09 x 2.97) + (2.93 x 2.53) + (2.57 x 0) + (3.92 x -0.496) = (2.09 + 2.93 + 2.57 + 3.92) Y

11.68 = 11.51 Y

Y = 11.68 / 11.51 = 1.02 m

7 0
3 years ago
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