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2 years ago

How much energy is needed to change the temperature of 50.0 g of water by 15.0oc?

1 answer:

3 0

The amount of energy needed to increase the temperature of a substance by $\Delta T$ is given by:
$Q=m C_s \Delta T$
where
m is the mass of the substance
Cs is the specific heat capacity of the substance
$\Delta T$ is the increase in temperature

In our problem, m=50.0 g, $C_s = 4.18 J/g ^{\circ}C$ (specific heat capacity of water) and $\Delta T=15.0 ^{\circ}C$ , therefore the amount of energy needed is
$Q=mC_s \Delta T=(50.0 g)(4.18 J/g^{\circ}C)(15.0^{\circ}C)=3135 J$

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PLEASE HELP ME WITH MY HOMEWORK!!!!!

IgorC [24]

Known :

l = 7 cm

w = 4 cm

Asked :

h = ...?

Answer :

V = B triangle × h (long)

35 = ½ × 4 × h × 7

35 = ½ × 28 × h

35 = 14 h

h = 35 ÷ 14

h = 2,5 cm

Sorry if I am wrong, I only study

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3 years ago

A 244.0 N block is at rest on a flat, frictionless table. A hooked cable applies an upward force of 24.0 N on the block. What is

blagie [28]

Answer:

268N

Explanation:

The upward force acting on the block are the reaction and the hooked table..

The total normal force acting = normal reaction + 24N

Note that the normal reaction is always equal the weight of the table

Hence the normal force acting in the block is 244.0+24 = 268.0N

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2 years ago

20% Part (a) Use an "E Field Sensor" and move it along either equipotential. What can you say about the E field along an equipot

Alex

Answer:

b. Constant magnitude, but varying direction, perpendicular to the equipotential.

Explanation:

As we know that the relation between electric field and electric potential is given as

$\Delta E = -\frac{dV}{dr}$

here if we say that potential is constant because electric field sensor is moving along equi-potential line.

Then we will say

V = constant

so we have

$\Delta E = 0$

so electric field will remain constant always in magnitude and always remains perpendicular to the surface

so we have

b. Constant magnitude, but varying direction, perpendicular to the equipotential.

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3 years ago

The American Psychological Association is the only organization that can approve psychological research studies.

pav-90 [236]

Answer: This is False.

Explanation:

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2 years ago

If a satellite weighs 321 lb. on the earth's surface (R = 4,000 miles), how much does it weigh 12,000 miles above the surface? (

Sever21 [200]

The gravitational force between the Earth and the satellite (its "weight") is inversely proportional to the distance between the centers of both objects.

On the surface, their centers are separated by 1 Earth radius.

12,000 miles above the surface, they're separated by 4 Earth radiii.

(4/1) = 4

So after the move, the satellite's weight is (1/4²) = 1/16 of its surface weight.

(321 lb) / (16) = (20 and a hair) lb

The correct choice from the given list is " <em>>20 lb "</em> .

3 0

2 years ago