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Simora [160]
3 years ago
7

This infectious disease is transmitted by a virus. Symptoms may vary, from a stuffy nose to coughing and a fever. This disease b

asically attacks the mucous membranes of the nose and throat but can attack the entire respiratory system. This infectious disease is
A)
asthma.


B)
diabetes.


C)
strep throat.


D)
the common cold.
Chemistry
2 answers:
mr Goodwill [35]3 years ago
5 0
This infectious disease is A, asthma
marissa [1.9K]3 years ago
4 0
The correct answer is A: Asthma
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Archy [21]

Answer:

The is less friction on an icy surface

Explanation:

This is because when u walk on plain ground there is steady friction on the surface but when u walk on an icy floor these is barely any friction which is why it's hard to walk on.

4 0
2 years ago
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7 0
3 years ago
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B. The heat of reaction for the process described in (a) can be determined by
julsineya [31]

Answer: I believe the 1st and 3rd reactions are better obtained through reference sources and the 2nd and 4th are easiest and safest to measure in the laboratory.

Explanation:

I am also working on this Pre-lab right now, and I looked back at the first question to help get my answer. In the first question (a), it is noted that ammonia gas and gaseous hydrochloric acid are both potentially dangerous in gaseous form. I saw that both the 1st and 3rd reactions contained noxious gases (I knew this because there was a (g) in both of these reactions). Using the knowledge from the first question that the noxious gases were potentially dangerous, I assumed that those reactions were the ones that are better obtained through the reference sources. The 2nd and 4th reactions did not contain any noxious gases, so I assumed those ones were easiest and safest to measure in the laboratory. Hope this helps!

7 0
4 years ago
How many kilocalories are required to increase the temperature of 15.6 g of iron from 122 °c to 355 °c. the specific heat of iro
Dmitriy789 [7]

Heat require to boil 15.6 g iron from 122 C0to 355 C0 whereas,

Q = m s dT

Where, m is mass of iron

s is specific heat of iron

d T is change in temperature in celcius

= 15.6 g * 0.45 J /g /C * (355 - 122)  = 1.63 * 10^3 J

If  

1 cal = 4.2 J

Then,  

Q = (1.63 * 10^3) /4.2 = 0.389 K cal

Thus 0.389 k cal of enrgy  is required by a 15.6 g Fe to reach to 355 C^0

4 0
4 years ago
Volume of water displaced = 0.175 L Mass g Density g/cm3 Hardness: = Determine the unknown mineral. Unknown mineral: 7​
erastovalidia [21]

Answer:

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Density: 5.61 g/cm^3

Hardness: = 2.5 - 3

Unknown material: Chalcocite

Explanation:

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3 years ago
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