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prisoha [69]
4 years ago
12

The pressure of 10.0 L of gas increases from 1.50 atm to 1240 mmHg. What is the final volume of the gas, assuming constant tempe

rature?
Chemistry
1 answer:
Zielflug [23.3K]4 years ago
7 0

Answer:

The final volume of gas is 9.19 L.

Explanation:

Given that,

Volume = 10.0 L

Initial pressure = 1.50 atm

Final pressure = 1240 mmHg

We need to calculate the final volume of gas

Using formula of ideal gas

P_{1}V_{1}=P_{2}V_{2}

V_{2}=\dfrac{P_{1}V_{1}}{P_{2}}

Where, P₁ = initial pressure

P₂ = final pressure

V₁ = initial volume

Put the value into the formula

V_{2}=\dfrac{1.50\times10\times760}{1240}

V_{2}=9.19\ L

Hence, The final volume of gas is 9.19 L.

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Combustion of hydrocarbons such as nonane () produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's atmosp
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Answer:

Part 1: C₉H₂₀ (l) + 14O₂ (g) ----> 9CO₂ (g) + 10H₂0 (g)

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<em>Note: the complete second part of the question is given below:</em>

<em>2. Suppose 0.470 kg of nonane are burned in air at a pressure of exactly 1 atm and a temperature of 17.0 °C. Calculate the volume of carbon dioxide gas that is produced. Round your answer to 3 significant digits.</em>

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Part 2: volume of carbon dioxide produced

From the equation of the reaction;

At s.t.p., I mole of  C₉H₂₀ reacts with 14 moles of O₂ to produce 9 moles of CO₂

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Volume of CO₂ gas produced at 1 atm and 17 °C;

Using P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂/P₂T₁

where P₁ = 1 atm, V₁ = 1151.50 L, T₁ = 273 K, P₂ = 1 atm, T₂ = 17 + 273 = 290 K

Substituting the values; V₂ = (1 * 1151.5 * 290)/(1 * 273)

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