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vazorg [7]
3 years ago
6

What is the competition and what are the types of symbiosis?

Chemistry
2 answers:
Burka [1]3 years ago
5 0
Symbiosis describes close<span> interactions between two or more different species. There are four main types of symbiotic relationships: mutualism, commensalism, parasitism and competition.</span>
Wittaler [7]3 years ago
5 0
Competition is the struggle between organisms to survive in a habitat with limited resources in the same place at the same time. Types of symbiosis are commensalism and mutalism. 
<span>
Commensalism—A relationship where one species obtains food or shelter from the other species.
<span>
Mutualism—A relationship where both species benefit from the relationship.</span></span>
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An insoluble solid that forms from a chemical reaction is called a(n)
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This description applies and is suitable for what a chemical precipitate is. A precipitate is a product that is formed from a certain chemicals reaction that yields a solid that is insoluble in the reaction vessel. It is usually white and opaque.
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Why do oxygen and sulfur have similar chemical properties?
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Answer:

Oxygen and sulfur have similar chemical properties because both elements have six electrons in their outermost electron shells. Indeed, both oxygen and sulfur form molecules with two hydrogen atoms: water and hydrogen sulfide

Explanation:

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What is the atomic mass of an atom that has 3 protons and 4 neutrons
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Thus the atomic mass = 3  +  4
  
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On the periodic table, what is used to determine the order of elements? (Use your own words? Help please!!!
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Read 2 more answers
A 1.52 g sample of KCIO3 is reacted according to the balanced equation below. How many liters of O2 is produced at a pressure of
ipn [44]

Answer:

0.486 L

Explanation:

Step 1: Write the balanced reaction

2 KCIO₃(s) ⇒ 2 KCI (s) + 3 O₂(g)

Step 2: Calculate the moles corresponding to 1.52 g of KCIO₃

The molar mass of KCIO₃ is 122.55 g/mol.

1.52 g × 1 mol/122.55 g = 0.0124 mol

Step 3: Calculate the moles of O₂ produced from 0.0124 moles of KCIO₃

The molar ratio of KCIO₃ to O₂ is 2:3. The moles of O₂ produced are 3/2 × 0.0124 mol = 0.0186 mol

Step 4: Calculate the volume corresponding to 0.0186 moles of O₂

0.0186 moles of O₂ are at 37 °C (310 K) and 0.974 atm. We can calculate the volume of oxygen using the ideal gas equation.

P × V = n × R × T

V = n × R × T/P

V = 0.0186 mol × (0.0821 atm.L/mol.K) × 310 K/0.974 atm = 0.486 L

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3 years ago
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