assume in a different experiment, you prepare a mixture containing 10.0 M FeSCN2+, 1.0 M H+, 0.1 MFe3+ and 0.1 M HSCN. Is the in
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Answer:
Explanation:
An empirical formula shows the smallest whole-number ratio of the atoms in a compound.
So, we must calculate this ratio. Since we are given the amounts of the elements in moles, we can do this in just 2 steps.
<h3>1. Divide </h3>The first step is division. We divide the amount of moles for both elements by the <u>smallest amount of moles</u>.
There are 0.300 moles of sulfur and 0.900 moles of oxygen. 0.300 is smaller, so we divide both amounts by 0.300
- Sulfur: 0.300/0.300= 1
- Oxygen: 0.900/0.300= 3
The next step is writing the formula. We use the numbers we just found as the subscripts. These numbers go after the element's symbol in the formula. Remember sulfur is S and there is 1 mole and oxygen is O and there are 3 moles.
- S₁O₃
This formula is technically correct, but we typically remove subscripts of 1 because no subscript implies 1 representative unit.
- SO₃
Answer:
3.6667
Explanation:
<u>For helium gas:</u>
Using Boyle's law
Given ,
V₁ = 3.0 L
V₂ = 9.0 L
P₁ = 5.6 atm
P₂ = ?
Using above equation as:
<u>The pressure exerted by the helium gas in 9.0 L flask is 1.8667 atm</u>
<u>For Neon gas:</u>
Using Boyle's law
Given ,
V₁ = 4.5 L
V₂ = 9.0 L
P₁ = 3.6 atm
P₂ = ?
Using above equation as:
<u>The pressure exerted by the neon gas in 9.0 L flask is 1.8 atm</u>
<u>Thus total pressure = 1.8667 + 1.8 atm = 3.6667 atm.</u>