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2 years ago

Which term describes a long-term weather pattern? air mass climate humidity front

Physics

2 answers:

sergejj [24]2 years ago

6 0

Answer:

climate

Explanation:

Climate is defined as an area's long-term weather patterns. The simplest way to describe climate is to look at average temperature and precipitation over time.

Leni [432]2 years ago

4 0

Answer:

Explanation:

The answer is Climate

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If a ball is thrown up at an initial speed of 40. m/s, how many seconds does it take to reach the top of its path?

natka813 [3]

Answer:

Time, t = 4.08 secs

Explanation:

Given the following data;

Initial velocity, U = 40m/s

To find the time, we would use the first equation of motion;

$V = U + at$

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Making time, t the subject of formula, we have;

$t = \frac{V - U}{a}$

We know that acceleration due to gravity, g is 9.8m/s².

a = g = - 9.8m/s² because the ball is thrown in the opposite direction.

Also, the final velocity is equal to zero (0) because the ball reached its maximum height.

Substituting into the equation, we have;

$t = \frac{0 - 40}{-9.8}$

$t = \frac{-40}{-9.8}$

Time, t = 4.08 secs

Therefore, it will take the ball 4.08 seconds to reach the top.

5 0

3 years ago

A. Calculate the electric potential energy stored in a capacitor that stores <img src="https://tex.z-dn.net/?f=3.40%20x%2010%5E%

sertanlavr [38]

Part a)

As we know that energy stored inside the capacitor is given as

$U = \frac{1}{2}CV^2$

for a given capacitor we know

$Q = CV$

Now we can use it in above equation to find the energy

$U = \frac{1}{2}QV$

$U = \frac{1}{2}(3.4\times 10^{-6})(24)$

$U = 40.8\times 10^{-6} J$

PART b)

If two negative charges are hold near to each other and then released

Then due to mutual repulsion they start moving away from each other

Due to mutual repulsion as the two charges moving away the electrostatic potential energy of two charges will convert into kinetic energy of the two charges.

So here as they move apart kinetic energy will increase while potential energy will decrease

Part c)

As we know that capacitance is given as

$C = \frac{Q}{V}$

here we know that

$Q = 3\times 10^{-10}C$

$V = 35 volts$

$C = \frac{3\times 10^{-10}}{35}$

$C = 8.6 \times 10^{-12} F$

5 0

3 years ago

Read 2 more answers

Following are the different layers of the Sun's atmosphere. Rank them based on the order in which a probe would encounter them w

Ghella [55]

Answer:

Sequence of layers to encounter while travelling from Earth to the surface of the sun are:

Option (A) - Corona

Option (C) - Chromosphere

Option (B) - Photosphere

Explanation:

Corona- It represents the extreme outer region of the surface of the sun. It is normally not visible because of the light emitted from the sun. So it is difficult to be seen from the naked eye, but it can be seen during the time of total solar eclipse. The temperature in this region is about several million degrees.

Chromosphere- It is a layer that lies between the Corona and the Photosphere. This layer has a thickness of about 2000 kilometers and the temperature in this layer ranges from about 6000°C to 20,000°C.

Photosphere- This layer is the bright visible layer of the sun which is comprised of plasma and dark and cool sunspots, that forms on the sun due to the emerging of the magnetic field of the sun from its surface.

Thus, the correct sequences are mentioned above.

3 0

3 years ago

a person hears an echo from the top of a tower , 2.2 second after the sound is produced.how far away is the tower from the perso

bekas [8.4K]

Answer:

730.4 m

Explanation:

The sound waves travels with a uniform motion (=constant velocity), therefore we can calculate the distance it travels using the formula:

$d=vt$

where

d is the distance

v is the speed of the sound wave

t is the time taken

In this problem we have:

v = 332 m/s is the speed of sound in air

t = 2.2 s is the time elapsed

Therefore, the distance between the tower and the person is

$d=(332)(2.2)=730.4 m$

5 0

3 years ago

A 2137 kg car moving east at 12.91 m/s collides with a 3264 kg car moving north. The cars stick together and move as a unit afte

IRINA_888 [86]

Answer:

The speed of the 3264 kg car before collision is 6.32 m/s

Explanation:

Let first car, mass m₁, moving east be moving with velocity, v₁ and second car, mass m₂, moving north be moving with velocity, v₂. Let the velocity of the two cars after collision be v₃

In a Collison (whether elastic or inelastic), momentum is always conserved.

Momentum before collision = momentum after collision.

Momentum before collision = m₁v₁ + m₂v₂

v₁ = (12.91î) m/s in vector form, m₁ = 2137 kg

v₂ = ?, v₂ = (v₂j) m/s in vector form, m₂ = 3264 kg

Momentum before collision = (2137)(12.91î) + (3264)(v₂j) = (27590î + 3264v₂j) kgm/s

Momentum after collision = (total mass of the cars after collision) × (velocity of the stuck-together cars after collision)

Total mass of the cars after collision = m₁ + m₂ = 2137 + 3264 = 5401 kg

Velocity after collision, v₃ = 6.38 m/s In the N36.8°E direction, put in vector form,

v₃ = (6.38 cos 36.8°î + 6.38 sin 36.8°j)

v₃ = (5.11î + 3.82j) m/s

Momentum after collision = 5401 (5.11î + 3.82j) = (27590î + 20641.4j) kgm/s

Momentum before collision = momentum after collision.

(27590î + 3264v₂j) = (27590î + 20641.4j)

Comparing components

3264v₂ = 20641.4j

v₂ = 6.32 m/s

Hope this Helps!!!

6 0

3 years ago