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Akimi4 [234]
3 years ago
5

A racehorse is running with a uniform speed of 69 km/hr along a straightaway. what is the time it takes for the horse to cover 4

00 meters?
Physics
2 answers:
Alex3 years ago
8 0
Hello there,
400 meters= 0.4 km
Time= Distance / speed
        = 0.4 / 69
        = 0.0057971014492754 hr
        = 0.35 min

Hope this helps :))

~Top
 
GREYUIT [131]3 years ago
5 0

Answer:

Time, t = 20.87 seconds

Explanation:

Given that,

Speed of the racehorse, v = 69 km/h = 19.16 m/s

Distance covered by the horse, d = 400 m

Let t is the time taken by the horse to cover 400 meters. It can be calculated using the definition of speed. Mathematically, the speed is given by :

v=\dfrac{d}{t}

t=\dfrac{d}{v}

t=\dfrac{400\ m}{19.16\ m/s}

t = 20.87 seconds

So, the time taken by the horse to cover 400 meters is 20.87 seconds. Hence, this is the required solution.

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3 0
3 years ago
Consider a large 1.54 V carbon-zinc dry cell used in a physics lab to supply 2.15 A to a circuit. The internal resistance of the
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<h2>Answer:</h2>

1.77V

<h2>Explanation:</h2>

The electromotive force voltage (E) in a cell, is related to the lost voltage (V_{L}) and the terminal voltage (V_{T}) as follows;

E = V_{T} - V_{L}

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<em>Substitute </em>V_{L}<em> =  I x r into equation (i) as follows;</em>

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<em>According to the question;</em>

E = 1.54V

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r = 0.105Ω

<em>Substitute these values into equation(ii) as follows;</em>

1.54 = V_{T} - (2.15 x 0.105)

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1.54 = V_{T} - 0.22575

<em>Solve for </em>V_{T}<em>;</em>

V_{T} = 1.54 + 0.22575

V_{T} = 1.54 + 0.22575

V_{T} = 1.77V

Therefore, the terminal voltage of the cell is 1.77V

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~~~ ╔͎═͓═͙╗
~~~ ╚̨̈́═̈́﴾ ̥̂˖̫˖̥  ̂ )
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