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3 years ago

Use the data table and information below to answer the following questions.

1 answer:

7 0

The temperature would be about 28°C based on the fact that the temperature of the dry sand has increased by 2 degrees during each 2-minute reading.

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1. A 46000N helicopter feels a net force of 9200N. What litt force is exerted by the air on the propellers?

Lina20 [59]

Answer:

Force exerted by the air on the propellers = 46000 - 9200

= 36800 N

Hope this helps!

4 0

4 years ago

Have thick walls<br>Chamaer o the heart<br>which

yulyashka [42]

I don’t get it explain

5 0

3 years ago

1. If you add air to a flat tire through a single small entry hole, why does the air spread out to fill the tire?

ikadub [295]

Answer:

The tire fills up just like anything else that holds air when u pump a ball or tire up it fills all the way up cause it is a small confined space and after filling it with air the atoms of the air fill the tire up

Explanation:

7 0

3 years ago

The Cartesian coordinate of a point in the xy plane are (x,y)=(-3.50,-2.50)m. Find the poler coordinate of this point

Masja [62]

Answer:

The polar coordinate of $P(x,y) = (-3.50\,m,-2.50\,m)$ is $P (r,\theta) = (4.301\,m, 215.538^{\circ})$ .

Explanation:

Given a point in rectangular form, that is $P(x,y) = (x,y)$ , its polar form is defined by:

$P(x,y) = (r,\theta)$ (1)

Where:

$r$ - Norm, measured in meters.

$\theta$ - Direction, measured in sexagesimal degrees.

The norm of the point is determined by Pythagorean Theorem:

$r = \sqrt{x^{2}+y^{2}}$ (2)

And direction is calculated by following trigonometric relation:

$\theta = \tan^{-1} \frac{y}{x}$ (3)

If we know that $x = -3.50\,m$ and $y = -2.50\,m$ , then the components of coordinates in polar form is:

$r = \sqrt{(-3.50\,m)^{2}+(-2.50\,m)^{2}}$

$r \approx 4.301\,m$

Since $x < 0\,m$ and $y < 0\,m$ , direction is located at 3rd Quadrant. Given that tangent function has a period of 180º, we find direction by using this formula:

$\theta = 180^{\circ}+\tan^{-1} \left(\frac{-2.50\,m}{-3.50\,m} \right)$

$\theta \approx 215.538^{\circ}$

The polar coordinate of $P(x,y) = (-3.50\,m,-2.50\,m)$ is $P (r,\theta) = (4.301\,m, 215.538^{\circ})$ .

5 0

3 years ago

6. And what's up with ChiN?

n200080 [17]

I don’t know what’s up with chin man ??

4 0

3 years ago