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LUCKY_DIMON [66]
3 years ago
11

A basketball player pushes down with a force of 34 N on a basketball that is inflated

Physics
1 answer:
zloy xaker [14]3 years ago
8 0

Answer:

2.2 cm

Explanation:

Pressure = force / area

P = F / A

A = F / P

A = 34 N / (9×10⁴ Pa)

A = 0.000378 m²

Area of a circle is:

A = πr²

0.000378 m² = πr²

r = 0.011 m

Diameter is double the radius:

d = 2r

d = 0.022 m

d = 2.2 cm

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2 years ago
A resonant circuit using a 286-nFnF capacitor is to resonate at 18.0 kHzkHz. The air-core inductor is to be a solenoid with clos
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Answer:

The inductor contains N = 523962.32 loops  

Explanation:

From the question we are told that

     The capacitance of the capacitor is  C =  286nF = 286 * 10^{-9} \  F

      The resonance frequency is  f = 18.0 kHz =  18*10^{3} Hz

       The diameter is  d =  1.1 mm = \frac{1.1 }{1000} = 0.00011 \ m

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Generally the inductance of this air-core inductor is mathematically represented as

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Where w is the angular speed mathematically given as

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So

            L =  \frac{1}{4 \pi ^2 f^2}

Now equating the both formulas for inductance

         \frac{\mu_o * N^2 \pi d^2}{4 l}  =  \frac{1}{4 \pi ^2 f^2}

making N the subject of  the formula

              N = \sqrt{\frac{1}{(2 \pi f)^2} * \frac{4 * l }{\mu_o * \pi d^2 C}  }

              N =  \frac{1}{2 \pi f} * \frac{2}{d} * \sqrt{\frac{l}{\pi * \mu_o * C} }

             

 Substituting value

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Hi There! :)


An equilibrium constant is not changed by a change in pressurea. True
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False! :P
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