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Nana76 [90]
3 years ago
10

A) How many joules of energy does a 100-watt light bulb use per hour? Express your answer using two significant figures.

Physics
1 answer:
kenny6666 [7]3 years ago
5 0

A) 3.6\cdot 10^5 J

The power used by an object is defined as

P=\frac{E}{t}

where

E is the energy used

t is the time elapsed

In this problem, we have

P = 100 W is the power of the light bulb

t = 1 h = 3600 s is the time elapsed

Solving for E, we find the amount of energy used by the light bulb:

E=Pt = (100 W)(3600 s)=3.6\cdot 10^5 J

B) 1.1 \cdot 10^2 m/s

The kinetic energy of an object is given by

K=\frac{1}{2}mv^2

where

m is the mass

v is the speed of the object

In this problem, we have a man of mass

m = 65 kg

we want its kinetic energy to be

E=3.6\cdot 10^5 J

Therefore, we can calculate its speed from the previous formula:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(3.6\cdot 10^5 J)}{65 kg}}=105.2 m/s = 1.1 \cdot 10^2 m/s

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Explanation:

Given parameters:

Distance hopped  = 84m

Displacement  = 84m due east

Time  = 7s

Unknown:

Speed of kangaroo  = ?

Velocity of kangaroo  = ?

Solution:

To solve this problem,

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Answer:

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Explanation:

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r_{f} = Final distance between asteroid and rock = 2823 km = 2823000 m

v_{i} = Initial speed of rock = 136 ms⁻¹

v_{f} = Final speed of rock = 392 ms⁻¹

m = mass of the rock

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Using conservation of energy

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(0.5) m v_{i}^{2} - \frac{GMm}{r_{i}} = (0.5) m v_{f}^{2} - \frac{GMm}{r_{f}} \\(0.5) v_{i}^{2} - \frac{GM}{r_{i}} = (0.5) v_{f}^{2} - \frac{GM}{r_{f}} \\(0.5) (136)^{2} - \frac{(6.67\times10^{-11}) M}{(7514000)} = (0.5) (392)^{2} - \frac{(6.67\times10^{-11}) M}{(2823000)} \\M = 4.582\times10^{21} kg

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So when you stand on the surface of this particular planet, you feel a force of gravity that is

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That's <em>(1/18)</em> as much as on Earth.

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