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Nana76 [90]
3 years ago
10

A) How many joules of energy does a 100-watt light bulb use per hour? Express your answer using two significant figures.

Physics
1 answer:
kenny6666 [7]3 years ago
5 0

A) 3.6\cdot 10^5 J

The power used by an object is defined as

P=\frac{E}{t}

where

E is the energy used

t is the time elapsed

In this problem, we have

P = 100 W is the power of the light bulb

t = 1 h = 3600 s is the time elapsed

Solving for E, we find the amount of energy used by the light bulb:

E=Pt = (100 W)(3600 s)=3.6\cdot 10^5 J

B) 1.1 \cdot 10^2 m/s

The kinetic energy of an object is given by

K=\frac{1}{2}mv^2

where

m is the mass

v is the speed of the object

In this problem, we have a man of mass

m = 65 kg

we want its kinetic energy to be

E=3.6\cdot 10^5 J

Therefore, we can calculate its speed from the previous formula:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(3.6\cdot 10^5 J)}{65 kg}}=105.2 m/s = 1.1 \cdot 10^2 m/s

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An electron (charge = –1.6 x 10–19 C) is moving at 3.0 x 105 m/s in the positive x direction. A magnetic field of 0.80 T is in t
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Answer:

F = 3.84*10^-34N ^j

Explanation:

In order to calculate the magnetic force on the electron you use the following formula:

\vec{F}=q\vec{v} \ X\ \vec{B}       (1)

q: charge of the electron = -1.6*10^-19C

B: magnitude of the magnetic field = 0.80T

v: speed of the charge = 3.0*10^5 m/s

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-^i X ^k = ^j

The magnetic force is in the ^j direction (+y direction).

The magnitude of the magnetic force is:

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