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Gre4nikov [31]
4 years ago
6

Please hurry i have 10 minutes!

Mathematics
1 answer:
otez555 [7]4 years ago
7 0

Answer:

X= 5

Step-by-step explanation:

You might be interested in
At which intervals is the function linear or nonlinear?
NeX [460]

Answer:

Linear                                    non-linear

x<2 , x>5                           2<x<5

Step-by-step  explanation:

When a function is linear then the graph is a straight line

When the function is not linear then the graph is like a curve

From x = - infinity to 2 the graph is a straight line

So from - infinity to 2, the function is linear, that is x<2 function is linear

from 2  to 5 the graph is like a curve , so it is not linear

2<x<5 , the function is not linear

From x = 5 to infinity the graph is a straight line

So from 5 to infinity, the function is linear, that is x>5 function is linear

5 0
3 years ago
Acidity is measured on the pH scale. The acidity of a substance is given by pH=−logH, where H is the concentration of Hydrogen i
frosja888 [35]

Answer:

[H^+] = Antilog[-6]

Step-by-step explanation:

Even though the question is incomplete, let us try to correctly derive the equation used to find the hydrogen ion concentration.

pH=−log[logH^+]

-pH = log[H^+]

[H^+] = Antilog[-pH]

Since pH =6

The equation is;

[H^+] = Antilog[-6]

8 0
3 years ago
Read 2 more answers
Given the binomials (x - 3), (x - 1), (x + 2), and (x + 3), which one is a factor of f(x) = 2x3 + 3x2 - 2x - 3?
spayn [35]

Answer:

(x-1) is factor of our function.

Step-by-step explanation:

We are given a function f(x)=2x^{3} +3x^{2} -2x-3 and we are asked to find the correct factor from the given options.

Let us factor out our polynomial.

2x^{3} +3x^{2} -2x-3

x^{2} (2x+3)-1(2x+3)

(x^{2} -1)(2x+3)

(x+1)(x-1)(2x+3)

Therefore, (x-1) is correct choice for factor of our polynomial.



3 0
4 years ago
Read 2 more answers
How do I show work for the circled question?
fenix001 [56]
You circle the area where it states the ending of the declined point. In this case, circle the 5 hours.
6 0
4 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3&#10;

has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
Read 2 more answers
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