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viktelen [127]
3 years ago
7

Why do leaf cells contain many choloroplasts?

Biology
1 answer:
natta225 [31]3 years ago
5 0
A) cells located in a leaf need more sunlight for photosynthesis
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The domestic cat genome contains 2.9×109 base pairs. The length of linker DNA in mammals is 50 base pairs. Approximately how man
IgorLugansk [536]

Answer:

Number of nucleosomes in 2.9 * 10^9bp is equal to 1.47 * 10^7

Explanation:

For wounding one nucleosome, total length of DNA required is equal to 146 bp

The length of  linker DNA in mammals is equal to 50 bp

Thus , the total length of DNA that confides between two nucleosome is equal to the sum of wounding length of DNA and the linker length

= 146 + 50\\= 196bp

Thus, in 196bp length of DNA, the total number of nucleosomes is equal to 1

Thus, number of nucleosomes in 2.9 * 10^9bp is equal to

\frac{2.9* 10^9}{196} \\1.47 * 10^7

8 0
3 years ago
Which of the following are properties of steroid hormones? I) Steroid hormones are lipid soluble and easily cross the phospholip
REY [17]

The correct answer is option I) Steroid hormones are lipid soluble and easily cross the phospholipid bilayer.

The steroid hormones are made up of steroid molecules, the steroid molecules are hydrophobic and lipid soluble. This property makes help the steroid molecule to cross the phospholipid bilayer membrane easily. The steroid molecule has a direct influence on the genome transcription, they act by binding with the DNA as a transcriptional factor.

6 0
3 years ago
Strawberry plants reproduce by using _____. fertilization stolons corms meiosis
fgiga [73]

Answer:

Stolons

Explanation:

Stolons are long stems that grow sideways from a strawberry plant. This is usually the method used for reproduction in strawberry plants.

I hope this answer helped you!

- hershy103

4 0
3 years ago
Which predator is typically found in Central Africa
koban [17]
Most probably a king cobra snake, which originates from yes Central Africa, especially in Kenya.
7 0
3 years ago
In a dihybrid cross of two heterozygous individuals, you expect a 9:3:3:1 phenotypic ratio in the offspring, but observe a ratio
almond37 [142]

Answer:

e. Epistatic interaction of the two genes

Explanation:

The 9:7 ratio is typical of the Duplicate Recessive Epistasis.

The expected phenotypic ratiio of the offsrping of a dihybrid cross is:

9 A_B_

3 A_bb

3 aaB_

1 aabb

In the Duplicate Recessive Epistasis, the A_bb, aaB_ and aabb individuals all have the same phenotype, making for the ratio 9:7. What those three genotypes have in common is that in all of them at least one of the two genes  is homozygous recessive (either <em>aa</em> or <em>bb</em>).

This usually happens one the products of genes A and B are enzymes of the same metabolic pathway.

Whenever both A and B are present, the pathway can produce the final product and a certain phenotype. However, if any of the dominant alleles is missing, the enzyme is not produced and therefore the final product of pathway is not produced, giving the other phenotype.

3 0
3 years ago
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