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olga2289 [7]
3 years ago
12

Two technicians are discussing scan-tool use. Technician A says that a special diagnostic interface device is needed to connect

the vehicle to the laptop computer. Technician B says that all of the computers in a modern vehicle are connected through an SAE-standard J1939 CAN (Central Area Network) or LAN (Local Area Network) connection. Who is correct?
A. Technician B only

B. Neither Technician A nor B

C. Both Technicians A and B

D. Technician A only

ANSWER: Both technicians are correct, I have taken the test.
Engineering
2 answers:
Anna71 [15]3 years ago
7 0

Answer:

both technicians are correct, I haven't taken the test

likoan [24]3 years ago
3 0

Answer:

C. Both Technicians A and B

Explanation:

C. Both Technicians A and B  because the reason given are correct. Technicians A reason is a olden method while Technician B method is new and can work for modern vehicle.

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A power cycle under development has two options for a condenser. One outputs saturated water and one outputs saturated vapor. Th
agasfer [191]

Answer:

408 J/kg

662696.7 J/kg

Explanation:

Workdone by compression process in a pump can be isothermally expressed as :

W = P_1V_1 \ In \frac{P_2}{P_1}

For water at inlet pressure 1. 0 bar;

the specific values for :

saturated vapor v_g = 1.694 m^2 kg

saturated liquid v_f = 0.001043 \  m^2 kg

∴ we have

P_1 = 1.0 bar = 1. 0 × 10⁵ N/m²

P_2 = 50 bar = 50  × 10⁵ N/m²

For saturated water output from condenser work; we have

W = P_1V_f \ In (\frac{P_2}{P_1})

W = (1.0*10^{-5})(0.001043) In ( \frac{50}{10} ) J/kg

W = 408 J/kg

For saturated vapor output from condenser

Work required :

W = P_1V_g \ In ( \frac{P_2}{P_1} )

W = 1.0*10^5*1.694 \ In ( \frac{50}{1.0}) J/kg

W = 662696.7 J/kg

5 0
3 years ago
Read 2 more answers
Which of the following identifies one factor that causes conventional tillage to actually be good for the environment?
Brums [2.3K]

Answer:

Farmers who use conventional tillage use compost more than other farmers.

Explanation:

Convectional tillage is good to the environment because it attains the following;

  • It increases porosity of the soil
  • It loosens the soil thus allowing proper root growth and air exchange
  • It is an effective way to incorporate manure and break sod fields
  • Tilled soils warm faster in spring
8 0
3 years ago
Which size of impurity atom, smaller impurity atom or larger impurity atom, when located near a dislocation, will nullify some o
svp [43]

Answer:

Smaller impurity atom will nullify some of the compressive strain of a dislocation in a crystal. Because, smaller impurity atoms located near a dislocation creates tensile strain on atoms around it thereby partially nullifying compressive strain at the dislocation.

4 0
3 years ago
Determine the enthalpy, volume and density of 1.0 kg of steam at a pressure of 0.5 MN/m2 and with a dryness fraction of 0.96
Viktor [21]

Answer:

Enthalpy, hsteam = 2663.7 kJ/kg

Volume, Vsteam = 0.3598613 m^3 / kg

Density = 2.67 kg/ m^3

Explanation:

Mass of steam, m = 1 kg

Pressure of the steam, P = 0.5 MN/m^2

Dryness fraction, x = 0.96

At P = 0.5 MPa:

Tsat = 151.831°C

Vf = 0.00109255 m^3 / kg

Vg = 0.37481 m^3 / kg

hf = 640.09 kJ/kg

hg = 2748.1 kJ/kg

hfg = 2108 kJ/kg

The enthalpy can be given by the formula:

hsteam = hf + x * hfg

hsteam = 640.09 + ( 0.96 * 2108)

hsteam = 2663.7 kJ/kg

The volume of the steam can be given as:

Vsteam = Vf + x(Vg - Vf)

Vsteam = 0.00109255 + 0.96(0.37481 - 640.09)

Vsteam = 0.3598613 m^3 / kg

From the steam table, the density of the steam at a pressure of 0.5 MPa is 2.67 kg/ m^3

5 0
3 years ago
A 12-ft circular steel rod with a diameter of 1.5-in is in tension due to a pulling force of 70-lb. Calculate the stress in the
padilas [110]

Answer:

The stress in the rod is 39.11 psi.

Explanation:

The stress due to a pulling force is obtained dividing the pulling force by the the area of the cross section of the rod. The respective area for a cylinder is:

A=\pi*D^2/4

Replacing the diameter the area results:

A= 17.76 in^2

Therefore the the stress results:

σ = 70/17.76 lb/in^2 = 39.11 lb/in^2= 39.11 psi

5 0
3 years ago
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