Answer:
408 J/kg
662696.7 J/kg
Explanation:
Workdone by compression process in a pump can be isothermally expressed as :

For water at inlet pressure 1. 0 bar;
the specific values for :
saturated vapor 
saturated liquid 
∴ we have
= 1.0 bar = 1. 0 × 10⁵ N/m²
= 50 bar = 50 × 10⁵ N/m²
For saturated water output from condenser work; we have
W = 
W = 
W = 408 J/kg
For saturated vapor output from condenser
Work required :

W = 
W = 662696.7 J/kg
Answer:
Farmers who use conventional tillage use compost more than other farmers.
Explanation:
Convectional tillage is good to the environment because it attains the following;
- It increases porosity of the soil
- It loosens the soil thus allowing proper root growth and air exchange
- It is an effective way to incorporate manure and break sod fields
- Tilled soils warm faster in spring
Answer:
Smaller impurity atom will nullify some of the compressive strain of a dislocation in a crystal. Because, smaller impurity atoms located near a dislocation creates tensile strain on atoms around it thereby partially nullifying compressive strain at the dislocation.
Answer:
Enthalpy, hsteam = 2663.7 kJ/kg
Volume, Vsteam = 0.3598613 m^3 / kg
Density = 2.67 kg/ m^3
Explanation:
Mass of steam, m = 1 kg
Pressure of the steam, P = 0.5 MN/m^2
Dryness fraction, x = 0.96
At P = 0.5 MPa:
Tsat = 151.831°C
Vf = 0.00109255 m^3 / kg
Vg = 0.37481 m^3 / kg
hf = 640.09 kJ/kg
hg = 2748.1 kJ/kg
hfg = 2108 kJ/kg
The enthalpy can be given by the formula:
hsteam = hf + x * hfg
hsteam = 640.09 + ( 0.96 * 2108)
hsteam = 2663.7 kJ/kg
The volume of the steam can be given as:
Vsteam = Vf + x(Vg - Vf)
Vsteam = 0.00109255 + 0.96(0.37481 - 640.09)
Vsteam = 0.3598613 m^3 / kg
From the steam table, the density of the steam at a pressure of 0.5 MPa is 2.67 kg/ m^3
Answer:
The stress in the rod is 39.11 psi.
Explanation:
The stress due to a pulling force is obtained dividing the pulling force by the the area of the cross section of the rod. The respective area for a cylinder is:

Replacing the diameter the area results:

Therefore the the stress results:
