Resultant displacement is 29.2 km at 
north of west
Explanation:
To solve the problem, we have to use the rules of vector addition, resolving first each vector along the x- and y- direction.
Taking east as positive x direction and north as positive y- direction, we have:
- First displacement is 25.5 km east, therefore its components are
- Second displacement is 41.0 km northwest, so its components are
So, the components of the resultant displacement are
And so, the magnitude is calculated using Pythagorean's theorem:
And the direction is given by
Where the angle is measured from the west direction, since Rx is negative.
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Answer:
0.480 seconds
Explanation:
The period is the time for 1 revolution. Writing a proportion:
14.4 s / 30.0 rev = t / 1 rev
t = 0.480 s
The period is 0.480 seconds.
It means that there's something else besides speed that contributes to reaction distance. So even when speed is zero, reaction distance is still not zero.
Answer:
The Rutherford model was made by Ernest Rutherford, to describe a atom. That is a brief explanation
Explanation:
Answer:
The impulse exerted by one cart on the other has a magnitude of 4 N.s.
Explanation:
Given;
mass of the first cart, m₁ = 2 kg
initial speed of the first car, u₁ = 3 m/s
mass of the second cart, m₂ = 4 kg
initial speed of the second cart, u₂ = 0
Let the final speed of both carts = v, since they stick together after collision.
Apply the principle of conservation of momentum to determine v
m₁u₁ + m₂u₂ = v(m₁ + m₂)
2 x 3 + 0 = v(2 + 4)
6 = 6v
v = 1 m/s
Impulse is given by;
I = ft = mΔv = m(
The impulse exerted by the first cart on the second cart is given;
I = 2 (3 -1 )
I = 4 N.s
The impulse exerted by the second cart on the first cart is given;
I = 4(0-1)
I = - 4 N.s (equal in magnitude but opposite in direction to the impulse exerted by the first).
Therefore, the impulse exerted by one cart on the other has a magnitude of 4 N.s.
