Total work energy on the input side is WE = Fs; where F is a force acting on a mass to push it s distance. This is the so-called work function. Let fs = we, which is the work energy (useful energy) attained as output when WE is input.
<span>From the conservation of energy WE = Fs = fs - kNs = Total Output energy. Net force f = F - kN where kN is friction force acting against the pushing (input) force F. In the real world, there is always friction at some level. That is kN > 0 always. </span>
<span>Thus Fs = (F - kN)s; kNs = the energy lost to friction where k is the friction coefficient and N is the normal force on the surface(s) where the friction is generated. By definition, efficiency = fs/Fs = useful work/work input. Clearly fs = Fs - kN < Fs . Thus efficiency = fs/Fs < 1.00, which means output fs < Fs the input whenever kN > 0, which in the real world it always is. </span>
<span>The short answer is...output is always less than input because of friction and, sometimes, other losses like wind drag (which is a form of friction anyway).</span>
P=I*E
Power (P)
Voltage (E)
<span>Amps (I)</span>
Answer:
u₂ = 32.29 m/s
Explanation:
m₁ = 12 kg
u₁ = 0 m/s
m₂ = 417 g = 0.417 kg
d = 15 cm = 0.15 m
μ = 0.40
u₂ = ?
It is an inelastic collision. After the collision
We can apply ∑ F = m*a for the system (m₁ + m₂)
where m = m₁ + m₂ = 12 kg + 0.417 kg = 12.417 kg
then
∑ F = - Ff = m*a
if
Ff = μ*N = μ*W = μ*(m*g) = μ*m*g
⇒ - μ*m*g = m*a ⇒ a = - μ*g = - 0.40*9.8 m/s² = - 3.92 m/s²
⇒ a = - 3.92 m/s²
Since vf = 0 m/s (for the system)
we use the equation
vf² = vi²+2*a*d ⇒ 0 = vi²+2*a*d ⇒ vi = √(-2*a*d)
⇒ vi = √(-2*(- 3.92 m/s²)*0.15 m)
⇒ vi = 1.0844 m/s
we can use the equation for an inelastic collision
m₁*u₁ + m₂*u₂ = (m₁ + m₂)*vs
since m = m₁ + m₂; u₁ = 0 m/s and vs = vi
we have
m₁*0 + m₂*u₂ = m*vi
⇒ u₂ = m*vi / m₂
⇒ u₂ = 12.417 kg*1.0844 m/s / 0.417 kg
⇒ u₂ = 32.29 m/s (→)
Answer:
Explanation:
As the current in the ire is towards right and the charge particle is above the wire, the direction of magnetic field due to the current carrying wire is perpendicularly outwards to the plane of paper. It is calculated by the Maxwell's right hand thumb rule. Now by using the Fleming's left hand rule, the direction of force is upwards.