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ohaa [14]
2 years ago
9

When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees

upon landing to reduce the force of the impact. A 75-kg man just before contact with the ground has a speed of 4.6 m/s. (a) In a stiff-legged landing he comes to a halt in 2.1 ms. Find the average net force that acts on him during this time. N (b) When he bends his knees, he comes to a halt in 0.09 s. Find the average force now. N (c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of these forces, find the force of the ground on the man in parts (a) and (b). stiff legged landing N bent legged landing

Physics
1 answer:
dolphi86 [110]2 years ago
6 0

Answer:

a) 1.725*10^5 N

b) 3.83*10^3 N

c) i) 173.24 kN

c) ii) 4.57 kN

Explanation:

See the attachment for calculations

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Answer:

a_y = 4.9\ m/s^2

Explanation:

Given,

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\dfrac{dz}{dy}=-\dfrac{1.5-1}{1}

\dfrac{dz}{dy}=-0.5

The differential form with the acceleration

\dfrac{dz}{dy}=\dfrac{-a_y}{a_z + g}

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g = 9.8 m/s²

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a_y = 9.8\times 0.5

a_y = 4.9\ m/s^2

Hence, Horizontal acceleration of the gasoline before gasoline would spill is equal to 4.9 m/s²

3 0
3 years ago
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kumpel [21]

Answer:

The  correct option is  H

Explanation:

From the question we are told that

    The index of refraction of  coating is  n_1

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Generally the condition for constructive for a thin film interference is mathematically represented

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Here  t represents the thickness

For minimum thickness  m =  0

So

           2 *  t  =0  + \frac{1}{2}\frac{\lambda}{n_1 }

=>        t  =\frac{\lambda}{4n_1 }

3 0
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