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Kisachek [45]
4 years ago
12

Antacids are used to relieve heartburn and sour stomach. Products like these commonly contain substances such as Mg(OH)2, Al(OH)

3, and CaCO3. What is it about these substances that soothe a burning stomach? (2 points)
Chemistry
1 answer:
Leokris [45]4 years ago
6 0

Answer:

They all react with acids.  

Explanation:

Thus, they decrease the concentration of stomach acid and provide heartburn relief.

The equations for the reactions are:

  1. Mg(OH)₂ + 2HCl ⟶ MgCl₂ + 2H₂O
  2. Al(OH)₃ + 3HCl ⟶ AlCl₃ + 3H₂O
  3. CaCO₃ +2HCl ⟶ CaCl₂ + H₂O + CO₂

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3 0
3 years ago
Consider the reaction between HCl and O2: 4HCl(g)+O2(g)→2H2O(l)+2Cl2(g) When 63.1 g of HCl is allowed to react with 17.2 g of O2
alina1380 [7]

Answer:

The limiting reactant for this reaction is the HCl

Explanation:

This is my reaction:

4HCl(g)+O2(g)→2H2O(l)+2Cl2(g)

Molar mass O2 = 32 g/mol

Molar mass HCl = 36,45 g/mol

Mass / Molar mass = Moles

Moles HCl : 63,1 g / 36,45 g/m = 1,73 moles

Moles O2: 17,2 g / 32g/m =  0,54 moles

4 moles of HCl react with 1 mol of O2, according to reaction, so

1,73 moles of HCl, are going to react with, how many moles of O2.

4 moles HCl ___ 1 mol O2

1,73 moles HCl ___ (1,73 . 1)/ 4 = 0,43 moles of O2

O2 is my excess reagent because I need 0,43 moles and I have 0,54 so I have moles in excess.

1 mol of O2 are going to react with 4 moles of HCl

0,54 moles of O2 are going to react with, how many moles of HCl ?

1 mol O2 ____ 4 moles HCl

0,54 mol O2 ___ (0,54 . 4)/ 1 = 2,16 moles

I need 2,16 moles to consume my moles of O2, but I only have 1,73 moles, tha's why the HCl is mi limiting reactant.

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