Answer The value of
and
is, 40.79 kJ and 37.7 kJ respectively.
Explanation :
Heat released at constant pressure is known as enthalpy.
The formula used for change in enthalpy of the gas is:

Now we have to calculate the work done.
Formula used :

where,
w = work done = ?
P = external pressure of the gas = 1 atm
= initial volume = 
= final volume = 
Now put all the given values in the above formula, we get:


Now we have to calculate the change in internal energy.



Thus, the value of
and
is, 40.79 kJ and 37.7 kJ respectively.
Answer:
Volume = mass/density
Rearrange the equation for Mass:
Mass = Volume x Density
That is one way you can do it
Conceptually, just look at the units, the wood block's density is 0.6<u>g/cm^3</u> while the volume is 2.2 <u>cm^3</u>
So if density is every gram per centimeter cubed, and the volume is at centimeter cubed, the logical thing to do would be to multiply the density by the volume to get the total mass.
0.6g/cm^3 x 2.2cm^3 = 1.32g
<u>Therefore the mass of the block of wood is 1.32g </u>
If your using Plato the correct answer is (A. It accepts protons)