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Mademuasel [1]
2 years ago
15

A researcher wants to show the effects of slight changes in pH on the reproductive rates of fish in a lake.

Chemistry
1 answer:
torisob [31]2 years ago
8 0
A table would show the exact values at certain times, while some kinds of graphs only show approximate values but for the “slight changes” it is best to have the exact numbers.
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Mixture are combination of two or more substances that can be​
ryzh [129]

Answer:

A mixture is the physical combination of two or more substances in which the identities are retained and are mixed in the form of solutions, suspensions, and colloids. ... Some mixtures can be separated into their components by using physical (mechanical or thermal) means.

Explanation:

5 0
3 years ago
Two scientists are debating how to classify a new animal species that they have discovered. They observe that the animal is capa
BaLLatris [955]

Answer:

A

Explanation:

7 0
2 years ago
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The volume of 7.91 M HCl needed to make 196.1 mL of 2.13 M HCl is ____.
kumpel [21]

Answer:

a) 52.8

Explanation:

M1V1 = M2V2

(7.91 M)(x ml) = (2.13 M) (196.1 ml)

(7.91M) (xml) = 417.693 M.ml

x ml = 417.693/ 7.91

x   =  52.8

6 0
3 years ago
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For the reaction ? Fe+? H2o ⇀↽? Fe3o4+? H2 , a maximum of how many grams of fe3o4 could be formed from 354 g of fe and 839 g of
Evgesh-ka [11]

The given reaction is:

3Fe + 4H2O → Fe3O4 + 4H2

Given:

Mass of Fe = 354 g

Mass of H2O = 839 g

Calculation:

Step 1 : Find the limiting reagent

Molar mass of Fe = 56 g/mol

Molar mass of H2O = 18 g/mol

# moles of Fe = mass of Fe/molar mass Fe  = 354/56 = 6.321 moles

# moles of H2O = mass of h2O/molar mass of H2O = 839/18 = 46.611 moles

Since moles of Fe is less than H2O;  Fe is the limiting reagent.

Step 2: Calculate moles of Fe3O4 formed

As per reaction stoichiometry:

3 moles of Fe form 1 mole of Fe3O4

Therefore, 6.321 moles of Fe = 6.321 * 1/ 3 = 2.107 moles of Fe3O4

Step 4: calculate the mass of Fe3O4 formed

Molar mass of Fe3O4 = 232 g/mol

# moles = 2.107 moles

Mass of Fe3O4 = moles * molar mass

= 2.107 moles * 232 g/mol = 488.8 g (489 g approx)

 


7 0
3 years ago
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Consider the equation: 2NO2(g) N2O4(g). Using ONLY the information given by the equation which of the following changes would in
Reika [66]
I believe the correct answer is the first option. To increase the molar concentration of the product N2O4, you should increase the pressure of the system. You cannot determine the effect of changing the temperature since we cannot tell whether it is an endothermic or an exothermic reaction. Also, decreasing the number of NO2 would not increase the product rather it would shift the equilibrium to the left forming more reactants. The only parameter we can change would be the pressure. And, since NO2 takes up more space than the product increasing the pressure would allow the reactant to collide more forming the product.
7 0
2 years ago
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