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Mademuasel [1]
3 years ago
15

A researcher wants to show the effects of slight changes in pH on the reproductive rates of fish in a lake.

Chemistry
1 answer:
torisob [31]3 years ago
8 0
A table would show the exact values at certain times, while some kinds of graphs only show approximate values but for the “slight changes” it is best to have the exact numbers.
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The motion of atoms and molecules that most affects temperature is
Oliga [24]
A solid to a liquid, the boiling of water, solid the water molecules vibrate condensed but as a liquid they are still isolated in a controlled area and also reflect off one another more, liquid to a gas they do not and move freely until condensation occurs
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3 years ago
A 4-inch, f/5 telescope has a 1-inch eyepiece focal. Its magnifying power is:
Gre4nikov [31]

Its magnifying power is: 4X 5X 9X 20X. A 4-inch, f/5 telescope has a 1-inch eyepiece focal. Its magnifying power is 9x. This answer has been confirmed as correct and helpful.

7 0
3 years ago
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Answer these questions based on 234. 04360 as the atomic mass of thorium-234. The masses for the subatomic particles are given.
nikdorinn [45]

The mass defect for the isotope thorium-234 if given mass is 234.04360 amu is 1.85864 amu.

<h3>How do we calculate atomic mass?</h3>

Atomic mass (A) of any atom will be calculated as:

A = mass of protons + mass of neutrons

In the Thorium-234:

Number of protons = 90

Number of neutrons = 144

Mass of one proton = 1.00728 amu

Mass of one neutron = 1.00866 amu

Mass of thorium-234 = 90(1.00728) + 144(1.00866)

Mass of thorium-234 = 90.6552 + 145.24704 = 235.90224 amu

Given mass of thorium-234 = 234.04360 amu

Mass defect = 235.90224 - 234.04360 = 1.85864 amu

Hence required value is 1.85864 amu.

To know more about Atomic mass (A), visit the below link:

brainly.com/question/801533

4 0
1 year ago
1. The electronegativities of the period-3 elements are listed on the transparency. Calculate the
Firdavs [7]
The correct answer is c. Please give me brainlest let me know if it’s correct or not thanks bye
8 0
3 years ago
What would the volume of a gas be at 150c if had of volume of 693 ml at 45 c​
Vlad1618 [11]

Answer:

Explanation:

T1 = 150°C = (150 + 273.15)K = 423.15K

T2 = 45°C = (45 + 273.15)K = 318K

V1 = 693mL = 693cm³

Applying Charle's law, the volume of a given gas is directly proportional to is temperature provided that pressure remains constant.

V = kT

V1 / T1 = V2 / T2

693 / 423.15 = V2 / 318

V2 = (693 * 318) / 423.15 = 520.79cm³

The new volume of the gas is 520.79cm³

6 0
3 years ago
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