Answer:
1. 504.8 g Al(NO3)3
2. 14.3 moles O2
Explanation:
1.
g = moles x molar mass = 2.37 x 212.996 = 504.8 g Al(NO3)3
MM Al(NO3)3 = 212.996 g/mol
2.
moles = mass : molar mass = 456.89: 32 = 14.3 moles O2
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Answer:
(a) ion-dipole
(b) hydrogen bond
(c) dipole-induced dipole
Explanation:
<em>What is the strongest type of intermolecular force between (imf) solute and solvent in each solution?</em>
<em />
<em>(a) CsCl(s) in H₂O(l)</em>
CsCl is a salt that dissociates in the ions Cs⁺ and Cl⁻. H₂O is a polar molecule. Then, the imf is ion-dipole.
<em>(b) CH₃-CO-CH₃(l) (acetone) in H₂O(l)</em>
Acetone is partially polar and H₂O is very polar. The electronegative O in acetone can interact with the H with a positive charge density of water. The resulting imf is hydrogen bond.
<em>(c) CH₃OH(l) in CCl₄(l)</em>
CH₃OH is polar and CCl₄ is nonpolar. CH₃OH will induce a dipole in CCl₄ and the resulting imf is dipole-induced dipole.
Answer: The mass of the silver block is 256 grams
Explanation:
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of silver = ?
= mass of water = 100.0 g
= final temperature = 
= temperature of silver = 
= temperature of water = 
= specific heat of silver = 
= specific heat of water= 
Now put all the given values in equation (1), we get
![-m_1\times 0.233\times (28.0-56.1)=[100.0\times 4.184\times (28.0-24.0)]](https://tex.z-dn.net/?f=-m_1%5Ctimes%200.233%5Ctimes%20%2828.0-56.1%29%3D%5B100.0%5Ctimes%204.184%5Ctimes%20%2828.0-24.0%29%5D)
Therefore, the mass of the silver block is 256 grams
Density is mass/ volume so 1300/743x10^3=.00174966
