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natali 33 [55]
3 years ago
7

Given the following equation:

Chemistry
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer27.9 gFeS

Explanation:

Note: This is for 16.0 Grams of Sulfer

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Choose all the answers that apply.
ziro4ka [17]

Explanation:

The term suspension means mixing of small and light particles together which are not dissolved in a fluid.

Therefore, clay, slit, and sand would be carried by suspension as they have small particles as compared to small pebbles and large rocks.

In a rock, there might be substance which are soluble in water. These soluble substances are therefore, continuously removed from the rock by the action of water.

Hence, holes will appear in the rock leading to rills and rough surface. Ultimately, the rock will either decompose or fall into pieces. On acidification of water by organic and inorganic solvents, the dissolution of rock increases.

Thus, it is concluded that in solution, rocks are dissolved by salts and acids.

5 0
3 years ago
Please help me complete the following word equations:) also write the balanced equation, full ionic equation, and net ionic equa
AVprozaik [17]

Explanation:

The states may differ depending on the reactions

6 0
3 years ago
Can you please help me?
lorasvet [3.4K]

Answer:

60 moles of NaF

Explanation:

The balanced equation for the reaction is given below:

Al(NO3)3 + 3NaF —> 3NaNO3 + AlF3

From the balanced equation above,

3 moles of NaF reacted to produce 1 mole of AlF3.

Therefore, Xmol of NaF will react to produce 20 moles of AlF3 i.e

Xmol of NaF = 3 x 20

Xmol of NaF = 60 moles

Therefore, 60 moles of NaF are required to produce 20 moles of AlF3.

4 0
3 years ago
Gaseous butane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If of water is produced from
krek1111 [17]

The given question is incomplete. The complete question is :

Gaseous butane reacts with gaseous oxygen gas  to produce gaseous carbon dioxide and gaseous water . If 1.31g of water is produced from the reaction of 4.65g of butane and 10.8g of oxygen gas, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.

Answer: 28.0 %

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of butane}=\frac{4.65g}{58g/mol}=0.080moles

\text{Moles of oxygen}=\frac{10.8g}{32g/mol}=0.34moles

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

According to stoichiometry :

13 moles of O_2 require 2 moles of butane

Thus 0.34 moles of O_2 will require=\frac{2}{13}\times 0.34=0.052moles  of butane

Thus O_2 is the limiting reagent as it limits the formation of product and butane is the excess reagent.

As 13 moles of O_2 give = 10 moles of H_2O

Thus 0.34 moles of O_2 give =\frac{10}{13}\times 0.34=0.26moles  of H_2O

Mass of H_2O=moles\times {\text {Molar mass}}=0.26moles\times 18g/mol=4.68g

{\text {percentage yield}}=\frac{\text {Experimental yield}}{\text {Theoretical yield}}\times 100\%

{\text {percentage yield}}=\frac{1.31g}{4.68g}\times 100\%=28.0\%

The percent yield of water is 28.0 %

6 0
4 years ago
Considering the combustion reaction of propane again, what mass of propane (C3Hg) is necessary to react with 4.53 g of oxygen? C
zimovet [89]

Answer:

1.25 g C3H8

Explanation:

edge lol

7 0
2 years ago
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