Answer:
5600N
Explanation:
Given parameters:
Mass of car = 700kg
Initial velocity = 10m/s
Final velocity = 30m/s
Displacement = 50m
Unknown:
Net force acting on the car = ?
Solution:
To find the force acting on a body, it is pertinent we know the mass and acceleration.
Force = mass x acceleration
Now;
Let us find the acceleration from the kinematics equations:
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the acceleration
S is the distance
30² = 10² + (2 x a x 50)
900 = 100 + 100a
100a = 800
a = 8m/s²
Therefore;
Force = 700 x 8 = 5600N
Answer:
0.25 m/s
Explanation:
Average velocity = change in displacement / change in time
v = (1.5 m − 2.5 m) / (6 s − 2 s)
v = -0.25 m/s
The average speed is 0.25 m/s.
Answer:
The 43kg student will be sliding at 1.79m/s opposite the direction the 34kg student is going.
Explanation:
Conservation of linear momentum!
The law of conservation of momentum says that in an isolated system, the momentum before must equal the momentum after:
.
For our two students
(notice the - sign in -2.4m/s, this means going to the left)
since the students were not moving at first, , therefore we have
solving for gives
Hence the 43kg student will be sliding at 1.79m/s to the right.
I dont know what you are asking sorry can u elaborate
The answer would be B.Moisture,unstable air,and a way for the surface air to rise