Answer:
The magnitude of the magnetic torque on the coil is 1.98 A.m²
Explanation:
Magnitude of magnetic torque in a flat circular coil is given as;
τ = NIASinθ
where;
N is the number of turns of the coil
I is the current in the coil
A is the area of the coil
θ is the angle of inclination of the coil and magnetic field
Given'
Number of turns, N = 200
Current, I = 7.0 A
Angle of inclination, θ = 30°
Diameter, d = 6 cm = 0.06 m
A = πd²/4 = π(0.06)²/4 = 0.002828 m²
τ = NIASinθ
τ = 200 x 7 x 0.002828 x Sin30
τ = 1.98 A.m²
Therefore, the magnitude of the magnetic torque on the coil is 1.98 A.m²
Hey there!
The correct answer to your question is: Intensity
The rate which light flows through a given area of space is referred to as its intensity. I<span>ntensity and wavelength are two factors which contribute to light energy.</span>
Thank you!
Answer:
The mass of the wheel is 2159.045 kg
Explanation:
Given:
Radius 
m
Force 
N
Angular acceleration 
From the formula of torque,
Γ 
(1)
Γ 
(2)
Find momentum of inertia 
from above equation,
Find the momentum inertia of disk,
Kg
Therefore, the mass of the wheel is 2159.045 kg
<span>In a
real machine, the work output is always less than the work input is true. The answer
is letter A. it follows the law of entropy where no energy can be converted completely
into work. Under this law, Carnot’s theorem states that Carnot’s engine can
perform 100% of work. However, no such engine has ever succeeded the conversion
of work into 100%. The greatest efficiency so far is at 80%. Because there will always be factors that
could affect the conversion of work. </span>
