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Alina [70]
3 years ago
12

A 85.4 kg ice skater is moving at 5.97 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole.

She then moves in a circle of radius 0.895 m around the pole. Find the force exerted by the rope on her arms. The acceleration of gravity is 9.8 m/s 2 . Answer in units of kN.
Physics
1 answer:
Nimfa-mama [501]3 years ago
5 0

Answer:

F_c=35.81kN

Explanation:

When the ice skater grabs the loose end of the rope, he experiences a centipretal force, where the speed he had before grabbing the rope is the tangential speed, this force is given by:

F_c=ma_c\\F_c=m\frac{(v_T)^2}{r}\\F_c=85.4kg\frac{(5.97\frac{m}{s})^2}{0.085m}\\F_c=35.81kN

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Answer:

<h2>\boxed{  \bold{ \purple{0.0769 \: kg \: }}}</h2>

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\sf{Potential   Energy ( P.E ) \:  =  \: 20.8 \: joule}

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\sf{mass = } ?

\sf{acceleration \: due \: to \: gravity = 9.68 \:  {metre \: per \: second}^{2} }

Now, let's find the mass:

\sf{PE  \:  =  mass \times gravity \:  \times  \: distance}

plug the values

⇒\sf{20.8 = m \times 9.8 \times 27.6}

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⇒\sf{20.8 = 270.48 \: m}

Swap the sides of the equation

⇒\sf{270.48m = 20.8}

Divide both sides of the equation by 270.48

⇒\sf{ \frac{270.48m}{270.48}  =  \frac{20.8}{270.48} }

Calculate

⇒\sf{0.0769} kg

Hope I helped!

Best regards!!

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