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Alina [70]
3 years ago
12

A 85.4 kg ice skater is moving at 5.97 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole.

She then moves in a circle of radius 0.895 m around the pole. Find the force exerted by the rope on her arms. The acceleration of gravity is 9.8 m/s 2 . Answer in units of kN.
Physics
1 answer:
Nimfa-mama [501]3 years ago
5 0

Answer:

F_c=35.81kN

Explanation:

When the ice skater grabs the loose end of the rope, he experiences a centipretal force, where the speed he had before grabbing the rope is the tangential speed, this force is given by:

F_c=ma_c\\F_c=m\frac{(v_T)^2}{r}\\F_c=85.4kg\frac{(5.97\frac{m}{s})^2}{0.085m}\\F_c=35.81kN

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Two identical satellites orbit the earth in stable orbits. one satellite orbits with a speed v at a distance r from the center o
wariber [46]
The available options are: (found the complete text on internet)
A- at a distance less than r
B- at a distance equal to r
C- at a distance greater than r

Solution:
The correct answer is C) at a distance greater than r.

In fact, the gravitational attraction between the satellite and the Earth provides the centripetal force that keeps the satellite in circular orbit, so we can write
G \frac{Mm}{r^2}=m \frac{v^2}{r}
where the term on the left is the gravitational force, while the term on the right is the centripetal force, and where
G is the gravitational constant
M is the Earth mass
m is the satellite mass
r is the distance of the satellite from the Earth's center
v is the satellite speed

Re-arranging the equation, we get
r= \frac{GM}{v^2}
and we see from this formula that, if the second satellite has a speed less than the speed v of the first satellite, it means that the denominator of the fraction is smaller, and so r is larger for the second satellite.
7 0
3 years ago
A moving rope (parallel to the slope) is used to pull skiers up the mountain. If the slope of the hill is 37" and friction is ne
Charra [1.4K]

Since rope is parallel to the inclined plane so here we can say that net force parallel to the person which is pulling upwards must counterbalance the component of weight of the person.

Now here we will do the components of the weight of the person

given that weight of the person = 500 N

now its components are

W_x = 500 cos37

W_y = 500 sin37

now here as we can say that one of the component is balanced here by the normal force perpendicular to plane

while the other component of the weight is balanced by the force applied on the rope

So here the force applied on the rope will be given as

F = W_y = 500 sin37

F = 300 N

so it apply 300 N force along the inclined plane

5 0
3 years ago
Find the direction of this vector
Alika [10]

Answer:

125 degrees

Explanation:

180 - 55 = 125 degrees

8 0
2 years ago
Temperature and kinetic energy have a_______relationship.
Alex73 [517]
The hotter an object is, the more kinetic energy it has, but i'm not sure what is the exact word missing??
8 0
3 years ago
Read 2 more answers
A block of mass m=1.2 kg is held at rest against a spring with a force constant k=730N/m. Initially the spring is compressed a d
igor_vitrenko [27]

Answer:

Explanation:

potential energy of compressed spring

= 1/2 k d²

= 1/2 x 730 d²

= 365 d²

This energy will be given to block of mass of 1.2 kg in the form of kinetic energy .

Kinetic energy after crossing the rough patch

= 1/2 x 1.2 x 2.3²

= 3.174 J

Loss of energy

= 365 d² - 3.174  

This loss is due to negative work done by frictional force

work done by friction = friction force x width of patch

= μmg d ,   μ = coefficient of friction , m is mass of block , d is width of patch

= .44 x 1.2 x 9.8 x .05

= .2587 J

365 d² - 3.174   = .2587

365 d² = 3.4327

d² = 3.4327 / 365

= .0094

d = .097 m

= 9.7 cm

If friction increases , loss of energy increases . so to achieve same kinetic energy , d will have to be increased so that initial energy increases so compensate increased loss .

5 0
3 years ago
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