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Alina [70]
4 years ago
12

A 85.4 kg ice skater is moving at 5.97 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole.

She then moves in a circle of radius 0.895 m around the pole. Find the force exerted by the rope on her arms. The acceleration of gravity is 9.8 m/s 2 . Answer in units of kN.
Physics
1 answer:
Nimfa-mama [501]4 years ago
5 0

Answer:

F_c=35.81kN

Explanation:

When the ice skater grabs the loose end of the rope, he experiences a centipretal force, where the speed he had before grabbing the rope is the tangential speed, this force is given by:

F_c=ma_c\\F_c=m\frac{(v_T)^2}{r}\\F_c=85.4kg\frac{(5.97\frac{m}{s})^2}{0.085m}\\F_c=35.81kN

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brainly.com/question/1213762

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