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3 years ago

Help pls thx!!!!!!! this is my last question i hope!

Physics

2 answers:

Sunny_sXe [5.5K]3 years ago

7 0

Left
hope this helps

irakobra [83]3 years ago

4 0

Answer:

Left

Explanation:

newtons is a measure of force. Since there is more newtons(force) pushing to the left, the object will move left. the 15 newtons cancel each other out, leaving only 5 newtons pushing to one side with no resistance.

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Help please

olga nikolaevna [1]

Answer:

6.8 m/ s^2

Explanation:

a = f / m

a = (67N - 6N) / 9 kg

a= 6.8 m/ s^2

8 0

3 years ago

I need help with these four problems.. anyone??

babunello [35]

1) 14g
2) 24 fl oz
3)10 cups
4)12 and 1/2 cups

8 0

3 years ago

5. A cheetah with a mass of 70 kg was clocked running at 72 mph (32 m's). How many joules of

blsea [12.9K]

Answer:

Kinetic energy = 35840 Joules

Explanation:

Given the following data;

Mass = 70kg

Velocity = 32m/s

To find the kinetic energy;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

$K.E = \frac{1}{2}MV^{2}$

Where, K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

$K.E = \frac{1}{2}MV^{2}$

Substituting into the equation, we have;

$K.E = \frac{1}{2}*70*32^{2}$

$K.E = \frac{1}{2}*70*1024$

$K.E = 35 * 1024$

K.E = 35840 Joules.

Therefore, the kinetic energy possessed by the cheetah is 35840 Joules.

7 0

3 years ago

A convex mirror has a focal length of 15cm. If the object is 35cm from the mirror and is 2cm tall, what is the magnification? Ro

Verizon [17]

Answer:

The magnification is 0.3

Explanation:

Given:

The focal length of the convex mirror, f = 15 cm

for convex mirror f = -f = -15 cm

The distance of object, u = 35 cm

Height of the object, h = 2 cm

Now, using the mirror formula, we have

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$

where, v is the distance of the image

on substituting the values, we get

$\frac{1}{-15}=\frac{1}{35}+\frac{1}{v}$

$-\frac{1}{v}=\frac{1}{35}-\frac{1}{-15}$

v = -10.5 cm

now, the magnification (m) is given as:

m = $-\frac{v}{u}$

on substituting the values, we get

m = $-\frac{-10.5}{35}$

m = 0.3

Hence, the magnification is 0.3

6 0

3 years ago

A 0.500-kg potato is fired at an angle of 80.0° above the horizontal from a PVC pipe used as a "potato gun" and reaches a height

lions [1.4K]

Answer:

(a) $47.15ms^{-1}$

(b) $2470.13ms^{-2}$

Explanation:

From Newton's second law of motion

F=ma where m is mass, a is acceleration and F is net force

Also from kinetic equation of motion, velocity and displacement are related using equation

$v^{2}=u^{2}+2sa$

Where v is final velocity, u is initial velocity, a is acceleration and s is displacement

From the free body diagram attached, final velocity at maximum height is 0 and initial velocity is $usin80^{o}$

Also, the vertical component can be written as

$v_{y}^{2} }=u_{y}^{2} } -2gs$ The negative sign before 2gs means displacement is opposite the gravitational force

Where g is acceleration due to gravity, $u_{y}$ is vertical component of initial velocity and $v_{y}$ is vertical component of final velocity

Since $v_{y}$ is 0

$u_{y}^{2} } =2gs$

s=110 and g is taken as 9.8

$u_{y}=\sqrt{2*9.8*110}=46.43275$

$u_{y}=46.43ms^{-1}$

Also, it's evident that the vertical component of initial velocity is $u_{y}=u_{i}sin \theta$ where $\theta$ is angle of projection and $u_{i}$ is resultant velocity