Answer:
This question is incomplete
Explanation:
This question is incomplete because of the absence of the time taken to complete one full cycle.
Frequency (<em>f</em>) will be calculated first as
<em>f </em>= <em>N </em>÷<em> t</em>
where <em>N </em>is the number of cycles and <em>t </em>is the time taken to complete one full cycle. The unit for frequency is Hertz (Hz).
To calculate the period, <em>T, </em>the formula below will be used
<em>T </em>= 1 ÷ <em>f</em>
The unit for period is secs
This question is incomplete, the complete question is;
Car B is rounding the curve with a constant speed of 54 km/h, and car A is approaching car B in the intersection with a constant speed of 72 km/h. The x-y axes are attached to car B. The distance separating the two cars at the instant depicted is 40 m. Determine: the angular velocity of Bxy rotating frame (ω).
Answer:
the angular velocity of Bxy rotating frame (ω) is 0.15 rad/s
Explanation:
Given the data in the question and image below and as illustrated in the second image;
distance S = 40 m
V
= 54 km/hr
V
= 72 km/hr
α = 100 m
now, angular velocity of Bxy will be;
ω
= V
/ α
so, we substitute
ω
= ( 54 × 1000/3600) / 100
ω
= 15 / 100
ω
= 0.15 rad/s
Therefore, the angular velocity of Bxy rotating frame (ω) is 0.15 rad/s
Vx = 2*cos30 = 1.73m's
Other words:
D = Vo*t = 1.4 * 21 = 31.5m. @ 30 Deg.
Dy = 31.5*sin30 = 15.75 m.
I would say it would be the weight read.
Only because the Control is the type of liquid and the constants are Size of object and amount of liquid