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vaieri [72.5K]
3 years ago
7

True or False A goal of humanist psychologists today is to help people reach their full potential.

Physics
1 answer:
Juli2301 [7.4K]3 years ago
8 0
True, because people should reach their full potential within themselves and human psychologist should help those that need help to reach it.
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You pick up a 3.4-kg can of paint from the ground and lift it to a height of 1.8 m. (a) how much work do you do on the can of pa
MariettaO [177]

(a) For the work-energy theorem, the work done to lift the can of paint is equal to the gravitational potential energy gained by it, therefore it is equal to

W=mg\Delta h

where m=3.4 kg is the mass of the can, g=9.81 m/s^2 is the gravitational acceleration and \Delta h=1.8 m is the variation of height. Substituting the numbers into the formula, we find

W=(3.4 kg)(9.81 m/s^2)(1.8 m)=60.0 J


(b) In this case, the work done is zero. In fact, we know from its definition that the work done on an object is equal to the product between the force applied F and the displacement:

W=Fd

However, in this case there is no displacement, so d=0 and W=0, therefore the work done to hold the can stationary is zero.


(c) In this case, the work done is negative, because the work to lower the can back to the ground is done by the force of gravity, which pushes downward. Its value is given by the same formula used in part (a):

W=mg \Delta h=(3.4 kg)(9.81 m/s^2)(-1.8 m)=-60.0 J

8 0
3 years ago
A 270,000 kg rocket in gravity -free space expels 270 kg of fuel by exerting a force of 360 N on it. Find the magnitude of the a
Brut [27]
F = m a 
360 = 270 x a
1.3 = a
4 0
3 years ago
An atom of uranium 238 emits an alpha particle (an atom of He) and recoils with a velocity of 1.895 * 10^ 5 m/sec . With velocit
lora16 [44]

<u>Answer:</u> The velocity of released alpha particle is 1.127\times 10^7m/s

<u>Explanation:</u>

According to law of conservation of momentum, momentum can neither be created nor be destroyed until and unless, an external force is applied.

For a system:

m_1v_1=m_2v_2

where,

m_1\text{ and }v_1 = Initial mass and velocity

m_2\text{ and }v_2 = Final mass and velocity

We are given:

m_1=238u\\v_1=1.895\times 10^{5}m/s\\m_2=4u\text{ (Mass of }\alpha \text{ -particle)}\\v_2=?m/s

Putting values in above equation, we get:

238\times 1.895\times 10^5=4\times v_2\\\\v_2=\frac{238\times 1.895\times 10^5}{4}=1.127\times 10^7m/s

Hence, the velocity of released alpha particle is 1.127\times 10^7m/s

4 0
3 years ago
Que es electromagnetico?
adoni [48]
Se llaman cuerpos eléctricos.
3 0
3 years ago
2- A student ran 135 meters in 15 seconds. What was the student's velocity?
RoseWind [281]

Answer:

9 Brainly hahaha ............huh

4 0
3 years ago
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