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vredina [299]
3 years ago
9

Enunciado del ejercicio n° 1

Physics
1 answer:
hoa [83]3 years ago
6 0

Answer:

34

Explanation:

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A proton is moving at 425 m/s. (a) How much work must be done on it to stop it? (A proton has a mass of 1.67×10−27 kg.) (b) Assu
Tpy6a [65]

Answer:

a)1.51*10^-22joules b) 1.89*10^-7m

Explanation:

Work done to stop the proton = the kinetic energy of the proton = 1/2 mv^2 = 1/2* 1.67*10^-27* 425*425 = 1.51* 10 ^ -22 joules

b) net force acting to stop the proton = 8.01*10^-16

Work done needed to stop the proton = net force acting opposite the motion * distance

Distance covered = need work done/ net force

Distance = 1.51*10^-22/8.01*10^-16= 1.89*10^-7m

8 0
3 years ago
Two men are trying to carry a wooden pole. If one of them is weaker than other, how can they carry the pole hence making small l
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Answer: Answer down below.

Explanation:

6 0
2 years ago
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A science teacher ran a marathon. After the race she showed her students the silver blanket she was given to keep her warm.A gro
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Answer:

the foiley like color doesn't absorb the heat it bounces off of it. it would be much better to have a black blanket

7 0
3 years ago
Một oto đang chuyển động thẳng đều với vận tốc 36km/h thì hãm phanh sau 20s thì ô tô dừng lại quãng đường oto đi được là
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36km/h=10m/s
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3 0
3 years ago
A car of mass m, traveling at constant speed, rides over the top of a round hill. How do the normal force of the road on the car
dybincka [34]

Answer:

The normal force will be lower than the gravitational force acting on the car. Therefore the answer is N < mg, which is <em>option B</em>.

Explanation:

Over a round hill, the centripetal force acting toward the the radius of the hill supports the gravitational force (mg) of the car. This notion can be expressed mathematically as follows:

At the top of a round hill

Normal force = Gravitational force - centripetal force

At the foot of a round hill

Normal Force = centripetal force + Gravitational force

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3 years ago
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