Answer:
The total distance is equal to the change in total position of the person, but the displacement of the person is zero.
Explanation:
- The distance is the total change in the positions of the toy robot. it is having only magnitude and it is a scalar quantity.
- The displacement is the difference between the final and initial position of the toy robot. it is a vector quantity having magnitude and direction
- Since the distance is the change in positions, so the magnitude of the distance will be equal to the up and down distance covered.
- If the toy robot travels in a straight line path and returns back to its original location, the magnitude of the distance and displacement doesn't depend on the speed of the toy robot.
Answer:12.8°c
Explanation:
specific heat capacity of copper(c)=0.39J*g°c
Mass(m)=20grams
Quantity of heat(Q)=100joules
Temperature rise(@)=?
@=Q/(mxc)
@=100/(20x0.39)
@=100/7.8
@=12.8°c
When it says something like 'on the verge of moving,' it means that the pulling force and static friction force and gravitational force all cancel out! Any more pulling force and it is ready to move!
At some point, you want F as a function of <span>μs</span>, to determine the force needed depending on the coefficient of static friction. This function, <span>F(<span>μs</span>)</span>, will rely on the angle θ as well, but we want to consider just one angle θ in every scenario. One value means it is constant.
But if we know the F, and we know <span>μs</span>, we can find what the constant angle θ must be!
If F is the pulling force, <span>FS</span> is the static friction force, and <span>FG</span> is gravitational force,
<span><span><span>Fnet</span>=0</span><span>=F+<span>FS</span>+<span>FG</span></span><span>=F+<span>FN</span><span>μs</span>+mgsinθ</span><span>=F+mgcosθ<span>μs</span>+mgsinθ</span><span>=0</span></span>
Then you can find <span>F(<span>μs</span>)</span>, but then there is the issue of solving for the θ<span> to make it true.</span>
Answer:
The answer is "83.1%".
Explanation:
Given:
Using formula:
Calculating the gravity on the Earth’s surface: