Answer:
245.45km in a direction 21.45° west of north from city A
Explanation:
Let's place the origin of a coordinate system at city A.
The final position of the airplane is given by:
rf = ra + rb + rc where ra, rb and rc are the vectors of the relative displacements the airplane has made. If we separate this equation into its x and y coordinates:
rfX = raX+ rbX + rcX = 175*cos(30)-150*sin(20)-190 = -89.75km
rfY = raY + rbY + rcT = 175*sin(30)+150*cos(20) = 228.45km
The module of this position is:
And the angle measure from the y-axis is:
So the answer is 245.45km in a direction 21.45° west of north from city A
20waves/57.1s = 0.350 Hz
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Answer:
48.22 kg
Explanation:
Applying the law of conservation of momentum,
Total momentum before collision = Total momentum after collision
Note: Since both skaters were initially at rest, then their total momentum before collision is equal to zero.
And the velocity of the second skater will be in opposite direction to the first.
0 = mv+m'v'.................... Equation 1
Where m = mass of the first skater, m' = mass of the second skater, v = final velocity of the first skater, v' = final velocity of the second skater.
make v' the subject of the equation
m' = -mv/v'................. Equation 2
Given: m = 62 kg, v = 0.7 m/s, v' = -0.9 m/s (opposite direction to the first)
Substitute into equation 1
m' = -62(0.7)/-0.9
m' = 48.22 kg
Particles begin to move out of their ordered arrangement due to energy. They are unable to escape because of external pressure pushing down on the liquid.
Answer:
B, he will fly off the other end
Explanation:
there is too much potential energy that transforms into kinetic energy for him to stay on the track.
