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katen-ka-za [31]

4 years ago

11

(5, 3) and (7, 3) are two coordinate points for a single object on a position-versus-time graph. Assume time is measured in seco

nds and distance in meters. What can be said about the object's position over time?
A. It did not move at all.
B. It moved 2 meters in 3 seconds.
C. It moved 3 meters in 2 seconds.
D. It moved 4 meters in 2 seconds.

2 answers:

Maru [420]4 years ago

6 0

Since the y axis stayed consistent, we can assume it did not move at all.
(So your answer would be A)

poizon [28]4 years ago

5 0

The answer for this question:I’m sure it’s A

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As heat exchanger is counter flow therefore

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$LMTD=\frac{\Delta T_1-\Delta T_2}{\ln (\frac{\Delta T_1}{\Delta T_2})}$

$LMTD=\frac{80-104}{\ln \frac{80}{104}}$

$LMTD=91.49^{\circ}C$

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$A=\frac{1.2\times 4.184\times 1000\times 60}{640\times 91.49}=5.144 m^2$

$A=\pi DL=5.144$

$L=\frac{5.144}{\pi \times 0.015}$

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