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katen-ka-za [31]
3 years ago
11

(5, 3) and (7, 3) are two coordinate points for a single object on a position-versus-time graph. Assume time is measured in seco

nds and distance in meters. What can be said about the object's position over time?
A. It did not move at all.
B. It moved 2 meters in 3 seconds.
C. It moved 3 meters in 2 seconds.
D. It moved 4 meters in 2 seconds.
Physics
2 answers:
Maru [420]3 years ago
6 0
Since the y axis stayed consistent, we can assume it did not move at all.
(So your answer would be A)
poizon [28]3 years ago
5 0
The answer for this question:I’m sure it’s A
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How much time does it take the cheetah to travel 500 meters, if its average speed is 70 meters per second?
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l=500m

speed=70m/s

t=?

t=500/70=7.14s

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Your brother is insisting that you’ll never hear a sound produced behind a barrier wall at the end of your yard you notice that
Tresset [83]

Answer

D.Diffraction

Explanation

Diffraction is a property that is experienced by waves when they come across a barrier when they are in motion.

The ways tends to curve behind the barrier. This is called diffraction of waves.

Now, sound is a wave and it also experience diffraction. . So the brother will be able to hear the sound due to diffraction

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0.5 m/s2

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Which term is applied to an object through which light passes?
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D

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A car is traveling at 108 km/h, stuck behind a slower car. Finally the road is clear and the car pulls over to make a pass. The
mezya [45]

Answer:

The average acceleration of the car is 2.143 meters per square second.

Explanation:

Let assume that car accelerates uniformly, in that case, we can obtain the value of acceleration by using the following equation of motion:

v = v_{o}+a\cdot t

Where:

v_{o} - Initial velocity, measured in meters per second.

v - Final velocity, measured in meters per second.

a - Acceleration, measured in meters per square second.

t - Time, measured in seconds.

Now, we clear acceleration within expression:

a = \frac{v-v_{o}}{t}

Initial and final velocities are now converted from kilometers per hour into meters per second:

v_{o} = \left(108\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}  \right)

v_{o} = 30\,\frac{m}{s}

v = \left(135\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}  \right)

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If we know that t = 3.5\,s, then, the average acceleration of the car is:

a = \frac{37.5\,\frac{m}{s}-30\,\frac{m}{s} }{3.5\,s}

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The average acceleration of the car is 2.143 meters per square second.

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3 years ago
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