Help please ASAP ONLY 1 question

Which of the following is inversely proportional to the gravitational force between two masses?

Mrrafil [7]

It is D, the distance between each object squared. We get this from solving for the force of gravity, which is

F = G((m1*m2)/(r^2)).

Here, you can see that the masses of the two objects are divided by their total distance apart from each other (r) squared.

6 0

3 years ago

Which term is defined as the change in the direction of light when it goes from one medium into a different medium?

Vaselesa [24]

Refraction is the term

8 0

3 years ago

A heat engine does 9200 J of work per cycle while absorbing 22.0 kcal of heat from a hightemperature reservoir. What is the effi

Morgarella [4.7K]

Answer: 9.9%

Explanation: efficiency = (work output /work input) × 100

Note that, 1 kilocalorie = 4184 joules, hence 22kcal = 22× 4184 = 92048 joules.

Work output = 9200 j and work input = 92048 j

Efficiency = (9200/92048) × 100 = 0.099 × 100 = 9.9%

4 0

3 years ago

When at rest, a ruler has a length of 12.0 inches. How fast (in m/s) must the ruler fly past you in order for it to shorten to 6

PIT_PIT [208]

Answer:

2.598× $10^8 m/sec$

Explanation:

The length of the contraction is given by $l=l_0\sqrt{1-\frac{v^2}{c^2}}$ here $l_0$ is length of the ruler at rest which is given as 12 inches

l is the length of the ruler in moving condition which is given as 6 inches c is the speed of the light and v is the velocity of the ruler.

$l=l_0\sqrt{1-\frac{v^2}{c^2}}$

$\frac{l}{l_0}=\sqrt{1-\frac{v^2}{c^2}}$

$1-(\frac{l}{l_0})^2=\frac{v^2}{c^2}$

$1-(\frac{6}{12})^2=\frac{v^2}{c^2}$

$0.866=\frac{v}{c}$

$v=0.866\times 3\times 10^8=2.598\times 10^8 m/sec$

3 0

3 years ago

the car starts from rest at s=0 and increases its speed at at=4m/s^2. Determine the time when the magnitude of acceleration beco

dem82 [27]

Answer:

Time = 5 seconds

Distance = 50 meters

Explanation:

Constantly Accelerated Motion

When the velocity of a moving object changes at a constant rate, called acceleration, the velocity changes in same amounts in the same times. The question has a mistake when asking when the acceleration is 20 m/s. If the acceleration is constant, the only variable that can change to that value is the velocity. The equation to calculate the speed is

$v_f=v_o+a.t$