<h2>Answer: 12.24m/s</h2>
According to <u>kinematics</u> this situation is described as a uniformly accelerated rectilinear motion. This means the acceleration while the car is in motion is constant.
Now, among the equations related to this type of motion we have the following that relates the velocity with the acceleration and the distance traveled:
(1)
Where:
is the Final Velocity of the car. We are told "the car comes to a stop after travelling", this means it is 0.
is the Initial Velocity, the value we want to find
is the constant acceleration of the car (the negative sign means the car is decelerating)
is the distance traveled by the car
Now, let's substitute the known values in equation (1) and find :
(2)
(3)
Multiplying by -1 on both sides of the equation:
(4)
(5)
Finally:
>>>This is the Initial velocity of the car
The three longest wavelengths for the standing waves on a 264-cm long string that is fixed at both ends are:
- 5.2 meters.
- 2.6 meters.
- 1.7meters.
Given data:
Length of the fixed string = 264cms = 2.64 meters
The wavelength for standing waves is given by:
λ = 2L/n
where,
- λ is the wavelength
- L is the length of the string
For n = 1,
= 5.2 meters
For n = 2,
= 2.6 meters
For n = 3,
= 1.7 meters
To learn more about standing waves: brainly.com/question/14151246
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First, we must find the vertical distance traveled upwards by the ball due to the throw. For this, we will use the formula:
2as = v² - u²
Because the final velocity v is 0 in such cases
s = -u²/2a; because both u and a are downwards, the negative sign cancels
s = 14.5² / 2*9.81
s = 10.72 meters
Next, to find the time taken to reach the ground, we need the height above the ground. This is:
45 + 10.72 = 55.72 m
We will use the formula
s = ut + 0.5at²
to find the time taken with the initial velocity u = 0.
55.72 = 0.5 * 9.81 * t²
t = 3.37 seconds
Answer:
31ohms
Explanation:
in a series u add all the ohms together
<h3><u>Answer</u>;</h3>
1600 years
<h3><u>Explanation</u>;</h3>
- Half life is the time taken for a radioactive isotope to decay by half of its original amount.
- We can use the formula; N = O × (1/2)^n ; where N is the new mass, O is the original amount and n is the number of half lives.
- A sample of radium-226 takes 3200 years to decay to 1/4 of its original amount.
Therefore;
<em>1/4 = 1 × (1/2)^n</em>
<em>1/4 = (1/2)^n </em>
<em>n = 2 </em>
Thus; <em>3200 years is equivalent to 2 half lives.</em>
<em>Hence, the half life of radium-226 is 1600 years</em>
