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3 years ago

Temperature

Physics

1 answer:

Orlov [11]3 years ago

8 0

Answer:

Particles spread apart, temperatue increases, pressure increases

Explanation:

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4 years ago

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A sample of helium (He) occupies 8.0 liters at 1 atm and 20.0◦C. What pressure is necessary to change the volume to 1.0 liters a

nevsk [136]

Apply the combined gas law

PV/T = const.

P = pressure, V = volume, T = temperature, PV/T must stay constant.

Initial PVT values:

P = 1atm, V = 8.0L, T = 20.0°C = 293.15K

Final PVT values:

P = ?, V = 1.0L, T = 10.0°C = 283.15K

Set the PV/T expression for the initial and final PVT values equal to each other and solve for the final P:

1(8.0)/293.15 = P(1.0)/283.15

P = 7.7atm

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3 years ago

A stationary boat in the ocean is experiencing waves from a storm. the waves move at 56 km/h and have a wavelength of 160 m, bot

Lera25 [3.4K]

The wavelength $\lambda$ of the wave is 160 m, and this is the distance between two consecutive crests. The boat is located at a crest of the wave, this means that the first trough is located 80 meters from the boat (because the distance between a crest and a trough is half the wavelength).

The speed of the wave is
$v=56 km/h = 15.6 m/s$
so the time the boat takes to reach the first trough is
$t= \frac{S}{v} = \frac{80 m}{15.6 m/s}=5.1 s$

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4 years ago

The gravitational force between the charged constituents of the atom is negligible compared with the electric force between them

katrin2010 [14]

Answer: The initial force is reduced a factor 1/4 when the separation between charge is doubled

Explanation: As it well known the electric force between two charges is given by:

Finitial=k*q1*q2/d^2 where d is the distance between charges and k is a constant

if the distance is doubled this means 2*dinitial thus the new force is equal to F initial* 1/4

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3 years ago

A 5 kg object near Earth's surface is released from rest such that it falls a distance of 10 m. After the object falls 10 m, it

makkiz [27]

Answer:D

Explanation:

Given

mass of object $m=5 kg$

Distance traveled $h=10 m$

velocity acquired $v=12 m/s$

conserving Energy at the moment when object start falling and when it gains 12 m/s velocity

Initial Energy $=mgh=5\times 9.8\times 10=490 J$

Final Energy $=\frac{1}{2}mv^2+W_{f}$

$=\frac{1}{2}\cdot 5\cdot 12^2+W_{f}$

where $W_{f}$ is friction work if any

$490=360+W_{f}$

$W_{f}=130 J$

Since Friction is Present therefore it is a case of Open system and net external Force is zero

An open system is a system where exchange of energy and mass is allowed and Friction is acting on the object shows that system is Open .

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3 years ago