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Verizon [17]
3 years ago
11

It takes 20 Joules of Work to push 4 coulombs of charges Across the filament of a bulb.'find the potential difference Across the

filament​
Physics
1 answer:
hjlf3 years ago
8 0

Answer:

V = 5 Volts

Explanation:

Given the following data;

Work done = 20 Joules

Charge = 4 Coulombs

To find the potential difference;

Mathematically, the work done in moving a charge is given by the formula;

W = qv

Where;

W is the work done

q is the quantity of charge

v is the potential difference

Substituting we have;

20 = 4 * v

V = 20/4

V = 5 Volts

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A block rests on a frictionless horizontal surface and is attached to a spring. When set into simple harmonic motion, the block
MariettaO [177]

Answer:

v₀ = 0.5058 m/s

Explanation:

From the question, for the block to hit the bottle, the elastic potential energy of the spring at the bottle (x = 0.08 m) should be equal to the sum of the elastic potential energy of the spring at x = 0.05 m and the kinetic energy of block at x = 0.05 m

Now, the potential energy of the block at x = 0.08 m is ½kx²

where;

k is the spring constant given by; k = ω²m

ω is the angular velocity of the oscillation

m is the mass of the block.

Thus, potential energy of the spring at the bottle(x = 0.08 m) is;

U = ½ω²m(0.08m)²

Also, potential energy of the spring at the bottle(x = 0.05 m) is;

U = ½ω²m(0.05m)²

and the kinetic energy of the block at x = 0.05 m is;

K = ½mv₀²

Thus;

½ω²m(0.08)² = ½ω²m(0.05)² + ½mv₀²

Inspecting this, ½m will cancel out to give;

ω²(0.08)² = ω²(0.05)² + v₀²

Making v₀ the subject, we have;

v₀ = ω√((0.08)² - (0.05)²)

So,

v₀ = 8.1√((0.08)² - (0.05)²)

v₀ = 0.5058 m/s

7 0
3 years ago
A gas has an initial volume of 212 cm^3 at a temperature of 293 K and a pressure of 0.98 atm. What is the final pressure of the
MatroZZZ [7]
For this we use general equation for gases. Our variables represent:

p- pressure
v-volume
t- temperature

P1V1/T1 = P2V2/T2

in this equation we know:
P1,V1 and T1, T2 and V2. 
We have one equation and 1 unknown variable.

P2 = T2P1V1/T1V2 = 1.1atm
8 0
2 years ago
Lionel makes a graphic organizer to compare the electric field around a positive charge with the electric field around a negativ
krek1111 [17]
X- points away from the charge
y- points in the direction of the force on the positive charge
z- points toward the charge
6 0
2 years ago
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Hammer falls off a roof top and strikes the ground with a certain kinetic energy. If it fell
Galina-37 [17]

Answer:

If the starting GPE is doubled than it's KE would also double.

6 0
2 years ago
Gravity is a force. Gravity is also an example of __________________. . . A.. a theory. . B.. an established procedure. . C.. a
MissTica
The correct answer to this question is C - Gravity is a force. Gravity is also an example of a universal law. Well, according to Isaac Newton, anyway. According to Newton's Law of Universal Gravitation, 'every point mass attracts every single point mass by a force pointing along the line intersecting both paths.'
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